quantities within them are to be taken, viz. when xa. And replacing t by p(x) and (x) by its value given in (149), we have where the square brackets indicate particular values of the quantities within them, viz. those which correspond to x = a. If p(x) = x − a = h, (151) becomes Taylor's series. As an example of (151), let f(x) = ex, $(x) = (x−1) (x−2), and let a = 2; then which gives the expansion of ex in ascending powers of (x-1) (x-2). Also if a = 1, we have which gives another expansion of ex in powers of (x−1) (x−2). 93.] A still more general form of expansion than that of Lagrange was discovered by Laplace, and is known by the name of Laplace's Theorem. Given y = F{+x þ(y)} ; it is required to find ƒ(y). Using the same notation of Maclaurin's Theorem as heretofore, we have [da], 1.2 x2 u = f(y); .. [u]o = ƒ{F(z)}. And by a process similar to that employed in the proof of Lagrange's Theorem, it may be shewn that and so on for other and for the nth terms; whence + dz x2 d (d.f{r(c)} (p{r(2)})2 } 1.2 + ... (152) dz dz As an example of this Theorem, let it be required to find e", whence, substituting in the formula (152), we have Laplace's Theorem, it will be observed, becomes Lagrange's, when F = 1; and Taylor's Series is also a particular case of Laplace's; for as y = F{z+x+(y)}; then y = F( + Ax) = F(z) + let (y) = a, and f(y) = y; d.r(z) ax d2.F(z) a2x2 and writing h for ax, we have + dz 1 + dz2 1.2 ... ; ... 94.] Another form of function which it is often necessary to expand by Maclaurin's Theorem is that in which a subsidiary variable z is introduced; and where we have two equations of the form y = f(z), and 2= $(x); (153) and wherein it is required to expand y in ascending powers of x. Using Lagrange's notation of derived-functions, we have d3y dx3 dry dx4 = = (154) (155) (156) · ƒ''' (≈) {Þ′(x)}3 +3ƒ" (z) 4′(x) p′′ (x) +ƒ'(z) q′′'(x), (157) ƒ'` (≈) {$'(x)}1+6ƒ""(z) {p′(x)}2 p′′(x)+3ƒ′′(z) {p′′ (x)}2 +4ƒ''(z) p′(x) p'''(x) + ƒ′(z) $''(x); (158) and so on. Now substituting these quantities in the several terms of Maclaurin's Series, (13), Art. 58, and putting a = 0, and introducing the corresponding value of z, we shall have the required series. To take a simple case, let and so on; but when x = 0, z=0; therefore using the square brackets in the same signification as heretofore, 95.] But in the case wherein z is a series of terms in ascending powers of x, the preceding expansion takes a particular form which deserves much attention; and gives rise to a process which has been called Derivation *; and on which Arbogast * This process, though called by the same name, is essentially different from that explained in Art. 18. The title of Arbogast's work is, Du Calcul des Dérivations; it was published at Strasbourg, An VIII. (1800.). has constructed his Calcul des Dérivations. It will be convenient to take the exponential series for the base-form of the series, and I shall accordingly assume so that the problem is, the expansion in ascending powers of In all these equations let x = 0; then z = αo, values of and y = f(ao); in whatever manner therefore the dy day dx' dr... given in (155), (156), (157), ... are com posed of ƒ (z), f'(z), ƒ"(z), ... combined with ; dz d2z d3z .... in the same manner will these values, when x = From this [day] differential of f(a) on the supposition that dao = a1; dx. is the 0 the second differential of f(a.) on the supposition that da。= a1, and dai: =α2; and [d] is the nth differential of f(ao) on the supposition that da。 a1, da1 = a2, da2 = a3, ... dan-1 = a. In this power of substituting new constants for the differentials of other constants does Arbogast's method of derivation consist. = If therefore we replace the successive coefficients of the powers of x in Maclaurin's Series, equation (13), Art. 58, by their values determined as above, we have the square brackets in this case indicating that particular values of the functions enclosed in them are to be taken, viz. when we replace dao by a1, da1 by ag, ...... And if we perform the several operations of derivation and introduce Lagrange's notation of derived-functions, we have +f' = = ƒ (ao) +ƒ'(av) a1} + {ƒ“ (ao) ar3 +ƒ′ (ao) a2} 1.2 x3 + {ƒ'"' (ão) aï3 +3ƒ" (ao) a1 a1⁄2 +ƒ'(ao) a3} + (163) 1.2.3 Of this process we propose to give a few examples. Ex. 1. It is required to expand in ascending powers of x x23 Ex. 2. It is required to develope (a+a11+a2 1.2). 1 x2 1 1.2 |