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whence, dividing through successively by dx and dy, and

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we have the ratio of the partial variations of u and of x, and of u and of y, and bracketing them to indicate that they are partial, we have

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vary when (du) is calculated, and a does

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is calculated, we must bear in mind that

dr de

du dy

are to be calculated on the supposition that dy = 0; dx' dx dr de

and that

dy' dy

are to be calculated on the supposition that dx=0. Let us introduce these conditions; from (178) we have

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successively do and dr between these two equations on this supposition, we have

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and if we substitute these quantities in the expressions above

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du

"), the resulting expressions will be the equi

dy

and

dy

when x and y are replaced by their

equivalents in terms of r and 0. It is unnecessary to express the values in their full length, because it is more convenient to work each example with its own particular formulæ.

dR

107.] Ex. 1. To transform (1) and

dR

dy

into their equi

valents in terms of r and 6, when ar cos 0, y = r sin 0.

In this problem there is implied a function, R = f(x, y), which becomes, when x and y are replaced by their equivalents,

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To calculate da, dy must be equal to 0; whence, eliminating

de and dr in turn from (187), we have

dx dr cos 0-r sin 0 do,

and therefore

0 = dr sin 0 + r cos 0 d0 ;

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Similarly to calculate dy, dx = 0; wherefore, by means of

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Hence we have two transformations useful in the Planetary Theory, viz.

dR

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dR (dR),

=

dy

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Ex. 2. It is required to transform into its equivalent in terms

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108.] The general formulæ for the transformation of second and higher partial differentials and derived-functions, which are analogous to those of Art. 107, are evidently very long; and as their discovery is easy, it will be sufficient for our purpose to give one or two examples wherein particular and the most common forms of them appear.

Ex. 1. To transform (d2) +

d2v

dy2

into its equivalent in

terms of r and 6, where x = r cos 0, y = r sin 0.

By the process of the preceding Article and (188), we have

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differentiating (191), and bearing in mind that

are functions of r and 0, we have

(dv) and (dv)

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The results (193) and (194) are no other than particular cases of equation (100), Art. 80, when the right substitutions are made, and consistently with the independence and equicrescence of the variables.

Also by a process similar to that by which (d) and have been found, it may be proved that

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dx2

d2v

dy2

sin cos 0/d2v

до 2

cos 20 (dv
(d).

(dx dy) = sin 0 cos 0

(

dr de)

(day)

(196)

r.2

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lent in terms of r, 0, and 4, when arsin cos p, y=rsin 0 sino,

2 = r cos 0.

It is convenient in this example to introduce a subsidiary quantity p, so that

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d2

1

1

1 dv

= ((xx) + 1 = (day) + /= (day) + (dr) + (dr); (200)

dr2

Ρ

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therefore substituting for p from (197) we have,

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To reduce this farther let cos 0μ; therefore cos-1μ; and

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=

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r2 (d2x) + 2r (dv) = r (dry),

dr2

so that (201) becomes

dr

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I may observe, see Ex. 3, Art. 102, that the given differential equation expresses a property of

V= {(x − a)2+(y—b)2 + (≈ —c)2} − §.

If in this we replace x, y, z by their values given in (197), we have

PRICE, VOL. I.

B b

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