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54.

(a + b −c)2 - d2 (b + c − a)2 - d2
+

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+

(c + a−b)2 — d2

(a + b)2 − (c + d)2 1 (b + c)2 − (a + d)2 + (c+a)2 − (b+d)2°

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61. If y+z

prove

C - -d

c2 d2

c2 + d2

a2 - b2

(iii.)

=

C-
- 2 d

a2 + b2

(iv.)

pa2 + qab + rb2

la2 + mab + nb2

pc2+qcd+rd2 Ic2+mcd+nd2

[ocr errors]

=

c2

(c + d) 2

Y =

2

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; then will x + y + z = 0.

=

ay+bz

2+x x+y
; then will each fraction =
az + bx ax+by

2 a+b

62. Prove that, if a, b, c be unequal, and

then will x + y + z = 0 and ax + by + cz = 0.

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CHAPTER XV.

EQUATIONS WITH FRACTIONS.

171. In the present chapter we shall give examples of equations which contain fractional expressions.

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We may multiply both sides of the equation by 120, the L. C. M. of the denominators of the fractions, without destroying the equality; we thus get rid of fractions, and have

24(x − 1) — 15 (3 x − 1) = 20 (43 − 5 x) ;

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The L. C. M. of the denominators is (x − 3) (x + 3) (x + 5). Multiplying both sides of the equation by the L. C. M.,* * we get rid of fractions, and have

(x+3)(x+5)+ 2 (x − 3) (x+5)=3(x-3) (x+3);

... x2 + 8x + 15 +

2x2 + 4x 303x2 - 27.

*See Art. 181.

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In this case it is best not to multiply at once by the L. C. M. of the denominators; the work is simplified by proceeding as under.

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which is the same equation as that in Ex. 3.

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x-2

х

X

1.

- 7

5

10

3x

1

[ocr errors]

1

2.

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