Geometrical Optics: Adapted to the Use of the Higher Classes in Schools, Etc |
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Page x
... Engine - Rotation and Translation Side Rod of Locomotive The Connecting Rod - Body rotating about an Axis , One Point Fixed - Gyroscope — The Spinning Top - Motion of Earth - Plane of Rotation Gyroscopic Action Explained Precessional ...
... Engine - Rotation and Translation Side Rod of Locomotive The Connecting Rod - Body rotating about an Axis , One Point Fixed - Gyroscope — The Spinning Top - Motion of Earth - Plane of Rotation Gyroscopic Action Explained Precessional ...
Page 22
... engine so that the table will balance . - 21. System of Parallel Forces in Space . If the forces are all parallel , it is evident that the resultant is equal in magnitude to the algebraic sum of the forces , and that its line of action ...
... engine so that the table will balance . - 21. System of Parallel Forces in Space . If the forces are all parallel , it is evident that the resultant is equal in magnitude to the algebraic sum of the forces , and that its line of action ...
Page 61
... engine is passing over a bridge , and when it is in the position shown in Fig . 61 one half of the load is carried by each truss . The weight of the engine is transmitted by the floor beams to the cross beams , and these are carried at ...
... engine is passing over a bridge , and when it is in the position shown in Fig . 61 one half of the load is carried by each truss . The weight of the engine is transmitted by the floor beams to the cross beams , and these are carried at ...
Page 252
... engine , and may be given any desired rotation . When this has been obtained , they may be disconnected and allowed to rotate . The dimensions and weight of the parts are known so that the kinetic energy of the fly wheel and rotating ...
... engine , and may be given any desired rotation . When this has been obtained , they may be disconnected and allowed to rotate . The dimensions and weight of the parts are known so that the kinetic energy of the fly wheel and rotating ...
Page 253
... engine becomes 1 / 12,600 1 ( 12,600 ) -- 1 ( 12,600 ) 2 + ( 1238 + 24 G ) 12 π 2 32.2 + ( 1233 +12,600 + 24 G ) ( .002 ) 2 π since there are no working forces . 33 n 24 7 n = 0 , 24 Problem 224. The speed is such as to correspond to a ...
... engine becomes 1 / 12,600 1 ( 12,600 ) -- 1 ( 12,600 ) 2 + ( 1238 + 24 G ) 12 π 2 32.2 + ( 1233 +12,600 + 24 G ) ( .002 ) 2 π since there are no working forces . 33 n 24 7 n = 0 , 24 Problem 224. The speed is such as to correspond to a ...
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a₁ acceleration angle angular velocity arrow axes axis of rotation axle center of gravity cloth coefficient of friction compression concurrent forces consider constant cord cosē couple Crown 8vo curve cylinder diameter direction disk distance dt dt Edition equal fcap Find the center fly wheel forces acting formula gravity axis hammer horizontal inch inertia with respect kinetic energy length lens line of action M₁ M₂ mass mirror moment of inertia motion moving P₁ P₂ pencil pendulum perpendicular plane point of application preceding problem prism pulley R₁ radians per second radius rays refraction represented resistance revolutions revolutions per minute rigid body seen shaft shown in Fig Simpson's Rule speed square Suppose surface T₁ tangential tension tion v₁ vertical weight work-energy equation x-axis zero