Geometrical Optics: Adapted to the Use of the Higher Classes in Schools, Etc |
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Page vii
... Resultant Two Concurrent Forces Resolution of Force - For Triangle - Force Polygon - Transmissibility of Forces . CHAPTER II ARTICLES 16-19 CONCURRENT FORCES · Concurrent Forces in a Plane Concurrent Forces i Space Moment of a Force ...
... Resultant Two Concurrent Forces Resolution of Force - For Triangle - Force Polygon - Transmissibility of Forces . CHAPTER II ARTICLES 16-19 CONCURRENT FORCES · Concurrent Forces in a Plane Concurrent Forces i Space Moment of a Force ...
Page 5
... Resultant of Two Concurrent Forces . If two forces having the same point of application act on a body , there is some single force that might be applied at the same point to produce the same effect . This single force is called the ...
... Resultant of Two Concurrent Forces . If two forces having the same point of application act on a body , there is some single force that might be applied at the same point to produce the same effect . This single force is called the ...
Page 6
... resultant . Algebraically R = √ P12 + P22 + 2 P1P2 cos AOB . 2 12. Resolution of Force . We have just seen how two concurrent forces may be replaced by a single force called their resultant . In a similar way a single force may be ...
... resultant . Algebraically R = √ P12 + P22 + 2 P1P2 cos AOB . 2 12. Resolution of Force . We have just seen how two concurrent forces may be replaced by a single force called their resultant . In a similar way a single force may be ...
Page 7
... resultant , and its ar . always away from the point of application . The equa opposite of this resultant would be a single force would hold the two concurrent forces in equilibriu 14. Force Polygon . current , we may find their resultant ...
... resultant , and its ar . always away from the point of application . The equa opposite of this resultant would be a single force would hold the two concurrent forces in equilibriu 14. Force Polygon . current , we may find their resultant ...
Page 8
... resultant of P1 and P2 , that OB represents the resultant of OA and P , and so of P1 , P and P , etc. That is , it is easy to see that the force poly- gon follows directly from the force triangle . By means of the force polygon it is ...
... resultant of P1 and P2 , that OB represents the resultant of OA and P , and so of P1 , P and P , etc. That is , it is easy to see that the force poly- gon follows directly from the force triangle . By means of the force polygon it is ...
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a₁ acceleration angle angular velocity arrow axes axis of rotation axle center of gravity cloth coefficient of friction compression concurrent forces consider constant cord cosē couple Crown 8vo curve cylinder diameter direction disk distance dt dt Edition equal fcap Find the center fly wheel forces acting formula gravity axis hammer horizontal inch inertia with respect kinetic energy length lens line of action M₁ M₂ mass mirror moment of inertia motion moving P₁ P₂ pencil pendulum perpendicular plane point of application preceding problem prism pulley R₁ radians per second radius rays refraction represented resistance revolutions revolutions per minute rigid body seen shaft shown in Fig Simpson's Rule speed square Suppose surface T₁ tangential tension tion v₁ vertical weight work-energy equation x-axis zero