Geometrical Optics: Adapted to the Use of the Higher Classes in Schools, Etc |
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Page 70
... speed , is directly pro- portional to their moments of inertia . The quantity , therefore , plays a very important part in the considera- tion of rotating bodies . In computing the strength of a beam or column it is necessary to ...
... speed , is directly pro- portional to their moments of inertia . The quantity , therefore , plays a very important part in the considera- tion of rotating bodies . In computing the strength of a beam or column it is necessary to ...
Page 123
... Speed is sometimes used instead of velocity , especially in speaking of the motion of machines or parts of machines . Speed , however , involves only the rate of motion without reference to the direction of motion , while velocity ...
... Speed is sometimes used instead of velocity , especially in speaking of the motion of machines or parts of machines . Speed , however , involves only the rate of motion without reference to the direction of motion , while velocity ...
Page 186
... problem of the sphere , Art . 105 , find the angular velocity at the end of 30 sec . and the reactions of the sup- ports for such speed . INGINEERS It 106. Center of Percussion . will be interesting 186 APPLIED MECHANICS FOR ENGINEERS.
... problem of the sphere , Art . 105 , find the angular velocity at the end of 30 sec . and the reactions of the sup- ports for such speed . INGINEERS It 106. Center of Percussion . will be interesting 186 APPLIED MECHANICS FOR ENGINEERS.
Page 199
... speed of rotation is six revolutions per second , we have w2 = 1421.29 and P = 199,122 lb. Dividing by F = 40 sq . in . , the area of cross section , we get the stress on the material in pounds per square inch as 4978 . Problem 169. If ...
... speed of rotation is six revolutions per second , we have w2 = 1421.29 and P = 199,122 lb. Dividing by F = 40 sq . in . , the area of cross section , we get the stress on the material in pounds per square inch as 4978 . Problem 169. If ...
Page 203
... speeds when the unbalanced mass is at all large . It is much the same in effect as the dropping of the weight on the ... speed of 100 mi . per hour , this lifting force would be about 10,980 lb. In 1 R A1 either case this weight applied ...
... speeds when the unbalanced mass is at all large . It is much the same in effect as the dropping of the weight on the ... speed of 100 mi . per hour , this lifting force would be about 10,980 lb. In 1 R A1 either case this weight applied ...
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Common terms and phrases
a₁ acceleration angle angular velocity arrow axes axis of rotation axle center of gravity cloth coefficient of friction compression concurrent forces consider constant cord cos² couple Crown 8vo curve cylinder diameter direction disk distance dt dt Edition equal fcap Find the center fly wheel forces acting formula gravity axis hammer horizontal inch inertia with respect kinetic energy length lens line of action M₁ M₂ mass mirror moment of inertia motion moving P₁ P₂ pencil pendulum perpendicular plane point of application preceding problem prism pulley R₁ radians per second radius rays refraction represented resistance revolutions revolutions per minute rigid body seen shaft shown in Fig Simpson's Rule speed square Suppose surface T₁ tangential tension tion v₁ vertical weight work-energy equation x-axis zero