Page images
PDF
EPUB

135. Many interesting identities can be established connecting the functions of the three angles A, B, C, which satisfy the relation A+B+C=180°. In proving these it will be necessary to keep clearly in view the properties of complementary and supplementary angles. [Arts. 39 and 96.]

From the given relation, the sum of any two of the angles is the supplement of the third; thus

[merged small][ocr errors][merged small]

A B

C

[blocks in formation]

Again, + + = 90°, so that each half angle is the comple

2 2 2

ment of the sum of the other two; thus

[blocks in formation]

Example 1. If A+B+C=180°, prove that

sin 24+ sin 2B + sin 2C-4 sin A sin B sin C.

The first side=2 sin (A + B) cos (A – B) + 2 sin C cos C

[blocks in formation]

Example 2. If A+B+C=180°, prove that

tan A+tan B+tan C-tan A tan B tan C.

[merged small][merged small][ocr errors][merged small][merged small][merged small]

whence by multiplying up and rearranging,

tan A+tan B+tan C=tan A tan B tan C,

[merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][subsumed][ocr errors][merged small][merged small][ocr errors][merged small][merged small][merged small][subsumed][merged small][subsumed][subsumed][ocr errors][merged small][subsumed][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small]

1.

sin 24 - sin 2B+ sin 2C-4 cos A sin B cos C.

2. sin 24-sin 2B- sin 2C-4 sin A cos B cos C.

[blocks in formation]

7. tantan+tan tan+tantan-1.

2

[merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small]
[blocks in formation]

9.

10.

cot
2 2'

cos 24+ cos 2B+cos 2C+4 cos A cos B cos C+1=0.

cot B cot C+ cot Ccot A+cot A cot B=1.

11. (cot B+cot C) (cot C+cot A) (cot A+cot B)

12. cos2 A+ cos2 B+cos2 C+ 2 cos A cos B cos C=1.

=cosec A cosec B cosec C.

[blocks in formation]

14. cos2 24+ cos2 2B+cos2 2C=1+2 cos 24 cos 2B cos 20.

[blocks in formation]

136. The following examples further illustrate the formulæ proved in this and the preceding chapter.

[blocks in formation]

cos (4+15°) cos (4 – 15°) – sin (A +15°) sin (A – 15°)

[blocks in formation]

NOTE. In dealing with expressions which involve numerical angles it is usually advisable to effect some simplification before substituting the known values of the functions of the angles, especially if these contain surds.

[ocr errors]
[merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][subsumed][merged small][subsumed][subsumed][subsumed][subsumed][ocr errors][merged small][merged small][subsumed][merged small]

Prove the following identities:

1. cos (a+B) sin (a-3)+cos (B+y) sin (8-y)

+cos (y+d) sin (y − 8)+cos (+a) sin (8 − a)=0.

[blocks in formation]

4. sin a cos (B+y) − sin ß cos (a+y)=cos y sin (a – ß).

5.

cos a cos (B+y) — cos ẞ cos (a+y)=sin y sin (a− ß). 6. (cos Asin A) (cos 24 - sin 2A)=cos A – sin 34.

[blocks in formation]

prove that a cos 20+b sin 20=a.

[See Art. 124.]

[blocks in formation]
[blocks in formation]
[ocr errors]

14. (2 cos A+1) (2 cos A − 1) (2 cos 24 − 1)=2 cos 44 +1. 15. tan (B-)+tan (y− a)+tan (a–B)

=tan (ẞ− y) tan (y — a) tan (a – B).

[blocks in formation]

=1+2 cos (B− y) cos (y − a) cos (a — ß).

18. cos2 a+cos2 B-2 cos a cos ẞ cos (a+B)=sin2 (a+ß). 19. sin2 a+sin2 ß+2 sin a sin ẞ cos (a+B)=sin2 (a+B). 20.

cos 12° + cos 60°+cos 84° = cos 24° + cos 48°.

If A+B+C=180°, shew that

[ocr errors]
[blocks in formation]

25. tan ẞ tan y+tan y tan a +tan a tan ẞ= 1.

« PreviousContinue »