Elementary Synthetic Geometry of the Point, Line and Circle in the Plane |
From inside the book
Results 1-5 of 42
Page 18
... perpendicular to one another , and each is perpendicular to the other . Perpendicularity is denoted by the symbol , to be read 18 SYNTHETIC GEOMETRY .
... perpendicular to one another , and each is perpendicular to the other . Perpendicularity is denoted by the symbol , to be read 18 SYNTHETIC GEOMETRY .
Page 19
Nathan Fellowes Dupuis. Perpendicularity is denoted by the symbol , to be read " perpendicular to " or " is perpendicular to . " A right angle is denoted by the symbol The symbol also denotes two right angles or a straight angle . Def ...
Nathan Fellowes Dupuis. Perpendicularity is denoted by the symbol , to be read " perpendicular to " or " is perpendicular to . " A right angle is denoted by the symbol The symbol also denotes two right angles or a straight angle . Def ...
Page 20
... perpendicular . q.e.d. Def . The perpendicular to a line - segment through its middle point is the right bisector of the segment . Since a segment has but one middle point ( 30 ° , Ex . 3 ) , and since but one perpendicular can be drawn ...
... perpendicular . q.e.d. Def . The perpendicular to a line - segment through its middle point is the right bisector of the segment . Since a segment has but one middle point ( 30 ° , Ex . 3 ) , and since but one perpendicular can be drawn ...
Page 21
... perpendicular to one another . EF and GH are bisectors of the LAOC ; then EF is 1 GH . Proof . LEOC = { 4AOC , and < COG = 34COB , OE is a bisector ; :: OG is a bisector ; adding , LEOG = AOB . But LAOB is a straight angle , :: LEOG is ...
... perpendicular to one another . EF and GH are bisectors of the LAOC ; then EF is 1 GH . Proof . LEOC = { 4AOC , and < COG = 34COB , OE is a bisector ; :: OG is a bisector ; adding , LEOG = AOB . But LAOB is a straight angle , :: LEOG is ...
Page 30
... perpendicular can be drawn to a line from a point not on the line . AB Proof . Let B be the point and AD the line ; and let BC be 1 to AD , and BA be any line other than BC . A C Then BCD is > < BAC , ( 60 ° ) BAC is not a , and BA is ...
... perpendicular can be drawn to a line from a point not on the line . AB Proof . Let B be the point and AD the line ; and let BC be 1 to AD , and BA be any line other than BC . A C Then BCD is > < BAC , ( 60 ° ) BAC is not a , and BA is ...
Other editions - View all
Common terms and phrases
ABCD Algebra altitude becomes bisects c.p.-circles centre of similitude chord of contact circles touch circumcircle co-axal coincide collinear concurrent concurrent lines concyclic congruent cut the circle denote diagonals diameter divided double points end-points equal angles equianharmonic equilateral triangle excircles external bisector fixed point geometric given circles given line given point harmonic range Hence hexagram homographic homologous hypothenuse incircle internal angles inverse points isosceles joins LAOB line-segment locus median middle point nine-points circle opposite sides orthogonally pair parallel parallelogram passes pencil perpendicular perspective plane point of contact point of intersection polar reciprocal Proof quadrangle radical axis radical centre radii radius rectangle rectilinear figure regular polygon rhombus right angle right bisector rotation secant similar Similarly square straight angle symbol tangent tensor theorem Theorem.-The three circles transversal vertex vertices