Elementary Trigonometry |
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Page 6
... perpendicular to AQ . Thus a right - angled triangle BAC is formed . With reference to the angle 4 the following definitions are em- ployed . BC opposite side hypotenuse The ratio or AB AC The ratio or AB BC The ratio or AC AC The ratio ...
... perpendicular to AQ . Thus a right - angled triangle BAC is formed . With reference to the angle 4 the following definitions are em- ployed . BC opposite side hypotenuse The ratio or AB AC The ratio or AB BC The ratio or AC AC The ratio ...
Page 9
... perpendicular to OA . Also take any point Fin OP and draw FG at right angles to OP . From the triangle BOC , sin POA = BC OB ' DE from the triangle DOE , sin POA : = OD FG from the triangle FOG , sin POA = OG But the triangles BOC , DOE ...
... perpendicular to OA . Also take any point Fin OP and draw FG at right angles to OP . From the triangle BOC , sin POA = BC OB ' DE from the triangle DOE , sin POA : = OD FG from the triangle FOG , sin POA = OG But the triangles BOC , DOE ...
Page 10
... perpendicular to BC and meets CA produced in D : if AB = 12 , AC = 16 , BC = 20 , find BD and CD . From the right - angled tri- angle CBD , BD = tan C ; BC from the right - angled triangle ABC , AB AC = tan C ; .. BD BC = AB AC 20 12 16 ...
... perpendicular to BC and meets CA produced in D : if AB = 12 , AC = 16 , BC = 20 , find BD and CD . From the right - angled tri- angle CBD , BD = tan C ; BC from the right - angled triangle ABC , AB AC = tan C ; .. BD BC = AB AC 20 12 16 ...
Page 14
... perpendicular to a b AC , and denote the sides of the right - angled triangle ABC by a , b , c . By definition , and BC α sin A = AB с AC b cos A = AB с a2 ... sin2 A + cos2 A - c2 + | b2 a2 + b2 c2 c2 COR . sin2A = 1 - cos2 A , cos2 A ...
... perpendicular to a b AC , and denote the sides of the right - angled triangle ABC by a , b , c . By definition , and BC α sin A = AB с AC b cos A = AB с a2 ... sin2 A + cos2 A - c2 + | b2 a2 + b2 c2 c2 COR . sin2A = 1 - cos2 A , cos2 A ...
Page 38
... perpendicular from C upon AB produced . Draw CD perpendicular to AB produced , and let CD = x . Then CBD = 180 ° - 135 ° = 45 ° ; .. BD = CD = x . Now in the right - angled tri- angle ADC , CD AD that is , -tan DAC = tan30 ° ; X 135 ...
... perpendicular from C upon AB produced . Draw CD perpendicular to AB produced , and let CD = x . Then CBD = 180 ° - 135 ° = 45 ° ; .. BD = CD = x . Now in the right - angled tri- angle ADC , CD AD that is , -tan DAC = tan30 ° ; X 135 ...
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Common terms and phrases
1+cos 1+tan² a+cos A+tan acute angle angle of elevation B+cos centre circle College cos² cos³ cosec cosine cot² cyclic quadrilateral decimal denote diff equal equation ex-central triangle Example expression Fcap feet Find the angle find the distance find the height Find the number Find the value flagstaff following identities formula given log greatest angle Hence horizontal plane hypotenuse inscribed LAOB loga logarithm magnitude miles negative number of radians observer pedal triangle perpendicular polygon positive Prof Prove the following quadrant quadrilateral radian measure radius vector regular polygon right angle right-angled triangle sec² sexagesimal shew sides sin sin sin sin² sin³ sine solution solve the triangle subtends an angle supplementary angles tan² tangent tower triangle ABC trigono trigonometrical functions trigonometrical ratios π π
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