Solutions of the Examples Appended to A Treatise on the Motion of a Rigid Body |
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Page 15
... applied in the reversed direction CO , there will be equilibrium between it , the weight , and the reaction of the axis . Since the two former forces are in the plane ABO , the latter reaction is in this plane also , and may be ...
... applied in the reversed direction CO , there will be equilibrium between it , the weight , and the reaction of the axis . Since the two former forces are in the plane ABO , the latter reaction is in this plane also , and may be ...
Page 24
... applied upwards the re- sultant of such reversed forces , together with R the initial reaction at the fixed point , can balance the weight Mg of the rod . .. Mg = R + Σ ( mr ) . ga a2 + k2 ' a2 = R + Mg , a2 + k3 1 = R + Mg , 1 + = R + ...
... applied upwards the re- sultant of such reversed forces , together with R the initial reaction at the fixed point , can balance the weight Mg of the rod . .. Mg = R + Σ ( mr ) . ga a2 + k2 ' a2 = R + Mg , a2 + k3 1 = R + Mg , 1 + = R + ...
Page 26
... applied at a point not in AB , this impulse will have an unbalanced moment about AB , and the conditions supposed are impossible . 21 . Let AB ( fig . 10 ) be the rod moving about 4 , and impinging at B on a vertical plane with an ...
... applied at a point not in AB , this impulse will have an unbalanced moment about AB , and the conditions supposed are impossible . 21 . Let AB ( fig . 10 ) be the rod moving about 4 , and impinging at B on a vertical plane with an ...
Page 27
... applied perpendicularly to the rod produces this angular velocity . The effective impulse applied to any molecule m at distance r from the axis is mrw , and such impulses reversed must balance R , because R is the only impressed force ...
... applied perpendicularly to the rod produces this angular velocity . The effective impulse applied to any molecule m at distance r from the axis is mrw , and such impulses reversed must balance R , because R is the only impressed force ...
Page 30
... applied at once to this case , the evaluation of the function would be troublesome in consequence of the discontinuous boundary which the area has when it is referred to rectangular axes . This difficulty is eluded by using polar co ...
... applied at once to this case , the evaluation of the function would be troublesome in consequence of the discontinuous boundary which the area has when it is referred to rectangular axes . This difficulty is eluded by using polar co ...
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2g h accelerating force Algebra angle angular velocity ball blow c² a² CA² Calculus Cambridge centre of gravity co-ordinate axes cone Conic Sections cos² cube cylinder diameter Differential Differential Calculus direction cosines disc distance dt dt dt dy dx dt dy dt effective force Examples Geometry Hence horizontal action horizontal and vertical HYMERS DR impulse inertia instantaneous axis invariable plane length Let C fig Ma² mass Mk² moment of inertia moves Mr² oscillation P₁ P₂ parallel particle perpendicular plates point of contact position pressure principal axes principle R₁ radius reaction revolves rotation sin² sphere tan² Third Edition Treatise velocities of translation vis viva w₁ w₂ wheel WHEWELL DR аф ᏧᎾ
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