A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 129
... accelerating force of gravity , and the time from the beginning of the motion . Let u represent the velocity of the body at the beginning of the two seconds during which its motion is observed : then , by the formula for falling bodies ...
... accelerating force of gravity , and the time from the beginning of the motion . Let u represent the velocity of the body at the beginning of the two seconds during which its motion is observed : then , by the formula for falling bodies ...
Page 130
... accelerating force , ( 1 ) when a second , ( 2 ) when a minute is taken as the unit of time . Let V denote the velocity acquired at the end of 3 seconds , and f the accelerating force , a second being taken as the unit of time . Then ...
... accelerating force , ( 1 ) when a second , ( 2 ) when a minute is taken as the unit of time . Let V denote the velocity acquired at the end of 3 seconds , and f the accelerating force , a second being taken as the unit of time . Then ...
Page 133
... accelerating force and the velocity at the beginning of the first interval . The measure of the accelerating force is 2 feet 6 inches , and the measure of the required velocity is one foot . ( 16 ) A particle moves over 7 feet , in the ...
... accelerating force and the velocity at the beginning of the first interval . The measure of the accelerating force is 2 feet 6 inches , and the measure of the required velocity is one foot . ( 16 ) A particle moves over 7 feet , in the ...
Page 134
William Walton. The accelerating force and velocity of projection are respec- tively equal to 2 ( m - n ) s and m- n2 Ꭶ ... accelerating force f in a body moving through a space s , when there is no initial velocity , therefore , by the ...
William Walton. The accelerating force and velocity of projection are respec- tively equal to 2 ( m - n ) s and m- n2 Ꭶ ... accelerating force f in a body moving through a space s , when there is no initial velocity , therefore , by the ...
Page 153
... accelerating force on a particle down AB is equal to 9 cos 0- μR m = g cos 0 - μg sin = = g ( cos 0 — cot w . sin 0 ) - = g - sin ( w- 0 ) sin w с = Hence the square of the velocity acquired down AB is equal to 2gc , a constant quantity ...
... accelerating force on a particle down AB is equal to 9 cos 0- μR m = g cos 0 - μg sin = = g ( cos 0 — cot w . sin 0 ) - = g - sin ( w- 0 ) sin w с = Hence the square of the velocity acquired down AB is equal to 2gc , a constant quantity ...
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attached axle beam bisect the angle centre of gravity chord coefficient of friction collision component cos² cylinder denote determine distance equal forces equation feet find the inclination find the position find the pressure fixed point forces act fulcrum geometrical given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum length lever line of quickest magnitude and direction middle point motion moveable parabola parallel parallelogram particle perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding sphere straight line string passing supposing suspended tan¹ three forces uniform rod University of Cambridge velocity of projection vertical plane wheel
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Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...