A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page ix
... Components along two lines at right angles to each other III . Components along any two lines not parallel IV . Friction 25 • ib . 26 · 35 ib . CHAPTER V. SECTION PAGE EQUILIBRIUM OF A BODY MOVEABLE ABOUT.
... Components along two lines at right angles to each other III . Components along any two lines not parallel IV . Friction 25 • ib . 26 · 35 ib . CHAPTER V. SECTION PAGE EQUILIBRIUM OF A BODY MOVEABLE ABOUT.
Page 2
... component forces and bisects the angle between them . ( 3 ) Two forces act on a point at right angles to each other and the resultant is double of the less : shew that the angle which the resultant makes with the less is double the ...
... component forces and bisects the angle between them . ( 3 ) Two forces act on a point at right angles to each other and the resultant is double of the less : shew that the angle which the resultant makes with the less is double the ...
Page 10
... and 48 pounds . ( 27 ) The resultant of two forces acting at right angles to each other is 13 pounds : when each component is increased by 3 pounds , the resultant is equal to the sum 10 RESULTANT OF TWO FORCES ACTING ON A POINT .
... and 48 pounds . ( 27 ) The resultant of two forces acting at right angles to each other is 13 pounds : when each component is increased by 3 pounds , the resultant is equal to the sum 10 RESULTANT OF TWO FORCES ACTING ON A POINT .
Page 11
... components ; to find the forces . The required components are forces of 5 pounds and 12 pounds . ( 28 ) Two equal weights P , P , are fixed to the ends of a string which passes over three tacks A , B , C , forming an equi- lateral ...
... components ; to find the forces . The required components are forces of 5 pounds and 12 pounds . ( 28 ) Two equal weights P , P , are fixed to the ends of a string which passes over three tacks A , B , C , forming an equi- lateral ...
Page 25
... , can be in equilibrium . Campion and Walton : Solutions of the Cambridge Problems of 1857 . W. S. 4 SECT . 2. Components along two lines at right angles CHAPTER IV EQUILIBRIUM OF ANY NUMBER OF FORCES ACTING ON A POINT Geometrical method.
... , can be in equilibrium . Campion and Walton : Solutions of the Cambridge Problems of 1857 . W. S. 4 SECT . 2. Components along two lines at right angles CHAPTER IV EQUILIBRIUM OF ANY NUMBER OF FORCES ACTING ON A POINT Geometrical method.
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accelerating attached balance ball beam body centre of gravity chord circle collision component cylinder denote descent described determine direction distance draw drawn Edition elasticity equal equation equilibrium extremity falling feet fixed forces act former friction fulcrum given point greatest ground hangs heavy hence horizontal plane inches inclined plane intersection join latter length lower magnitude mass meet middle point motion moving opposite parallel particle passes placed portion position of equilibrium pounds pressure produce projection proportional prove pully radius ratio reaction represented respectively rest resultant right angles ring rough seconds SECT shew sides sliding smooth space sphere square straight line string supported supposing suspended tension three forces triangle uniform unit velocity vertical vertical plane wall weight wheel whole
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Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...