A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
From inside the book
Results 1-5 of 29
Page 4
... meet in T , and draw OE , OF , parallel to DC , AB , respectively . L L The angle OBE is equal to ¿ AOB + ¿ BAO , and there- fore to DOC + BAC , and therefore to DOC + BDC , or to DOC + CDO , and therefore to OCF . Also BEO = CFO ...
... meet in T , and draw OE , OF , parallel to DC , AB , respectively . L L The angle OBE is equal to ¿ AOB + ¿ BAO , and there- fore to DOC + BAC , and therefore to DOC + BDC , or to DOC + CDO , and therefore to OCF . Also BEO = CFO ...
Page 22
... meet the circle in F and join BF . Complete the parallelogram BFOK . Then the force KO is equivalent to forces BO , KB , applied at O , that is , to forces BO , OF , that is , to the two forces BO , CO . Let E be the intersection of the ...
... meet the circle in F and join BF . Complete the parallelogram BFOK . Then the force KO is equivalent to forces BO , KB , applied at O , that is , to forces BO , OF , that is , to the two forces BO , CO . Let E be the intersection of the ...
Page 27
... : draw CH vertically to meet the horizontal line AB in H. Let W the given weight , and T ' = the tension of the string . Let ACH = 0 , ‹ BCH = 4. Then , since the = ring C is kept at rest by the tensions in FORCES ACTING ON A POINT . 27.
... : draw CH vertically to meet the horizontal line AB in H. Let W the given weight , and T ' = the tension of the string . Let ACH = 0 , ‹ BCH = 4. Then , since the = ring C is kept at rest by the tensions in FORCES ACTING ON A POINT . 27.
Page 76
... meet the horizontal line through A in the point D : let LADB = 0 . Then , from the triangles BAH , CAH , we have BH AH sin ‹ BAH sin B cos ( B + 0 ) sin B " and CH sin CAH cos ( C - · 0 76 CENTRE OF GRAVITY . Body supported at a point.
... meet the horizontal line through A in the point D : let LADB = 0 . Then , from the triangles BAH , CAH , we have BH AH sin ‹ BAH sin B cos ( B + 0 ) sin B " and CH sin CAH cos ( C - · 0 76 CENTRE OF GRAVITY . Body supported at a point.
Page 80
... meet GO , drawn vertically through the middle point G of the rod , and join 40 : produce OG to meet AC in H. Then the weight of the rod , supposed to be collected at G , the reaction of the wall , and the pressure exerted on the rod at ...
... meet GO , drawn vertically through the middle point G of the rod , and join 40 : produce OG to meet AC in H. Then the weight of the rod , supposed to be collected at G , the reaction of the wall , and the pressure exerted on the rod at ...
Other editions - View all
Common terms and phrases
accelerating attached balance ball beam body centre of gravity chord circle collision component cylinder denote descent described determine direction distance draw drawn Edition elasticity equal equation equilibrium extremity falling feet fixed forces act former friction fulcrum given point greatest ground hangs heavy hence horizontal plane inches inclined plane intersection join latter length lower magnitude mass meet middle point motion moving opposite parallel particle passes placed portion position of equilibrium pounds pressure produce projection proportional prove pully radius ratio reaction represented respectively rest resultant right angles ring rough seconds SECT shew sides sliding smooth space sphere square straight line string supported supposing suspended tension three forces triangle uniform unit velocity vertical vertical plane wall weight wheel whole
Popular passages
Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...