A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
From inside the book
Results 1-5 of 22
Page 3
... circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be RESULTANT OF TWO FORCES ACTING ON A POINT .
... circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be RESULTANT OF TWO FORCES ACTING ON A POINT .
Page 5
... proportional to these sides ; prove that their resultant passes through the intersection of the two other sides . SECT . 2. Trigonometrical Method . Let two forces P , Q , act upon a point , and let a be the angle between their ...
... proportional to these sides ; prove that their resultant passes through the intersection of the two other sides . SECT . 2. Trigonometrical Method . Let two forces P , Q , act upon a point , and let a be the angle between their ...
Page 9
... proportional between its greatest and least value . If P be not less than Q , the required angle is equal to · COS ( - ) . ( 21 ) Two equal forces act on a particle , first at an angle of 45 ° to each other , and next at an angle of 90 ...
... proportional between its greatest and least value . If P be not less than Q , the required angle is equal to · COS ( - ) . ( 21 ) Two equal forces act on a particle , first at an angle of 45 ° to each other , and next at an angle of 90 ...
Page 12
... proportional to the sides BC , CA , AB , of a triangle ABC , and of which the directions are either parallel to these sides or respectively in- clined to them at equal angles , act upon a point , they will pro- duce equilibrium , and ...
... proportional to the sides BC , CA , AB , of a triangle ABC , and of which the directions are either parallel to these sides or respectively in- clined to them at equal angles , act upon a point , they will pro- duce equilibrium , and ...
Page 13
... the three perpendiculars drawn from the angles of a triangle to the opposite sides , and their magnitudes inversely proportional to these perpendiculars : to prove that the three EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 13.
... the three perpendiculars drawn from the angles of a triangle to the opposite sides , and their magnitudes inversely proportional to these perpendiculars : to prove that the three EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 13.
Other editions - View all
Common terms and phrases
attached body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometry given circle given point hence highest point horizontal plane inclined plane intersection join latus rectum length lever line of quickest lowest point magnitude and direction middle point motion moveable parabola parallel particle pendulum perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles seconds SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ three forces uniform rod University of Cambridge velocity of projection vertical circle vertical plane wheel
Popular passages
Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...