A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page x
... supported at a point . CHAPTER VII . EQUILIBRIUM OF A BODY ACTED ON BY THREE FORCES CHAPTER VIII . · 56 ib . 62 74 • 76 · 79 EQUILIBRIUM OF A SYSTEM OF BODIES · 13 91 CHAPTER IX . MECHANICAL POWERS • 109 ib . I. Wheel and axle II ...
... supported at a point . CHAPTER VII . EQUILIBRIUM OF A BODY ACTED ON BY THREE FORCES CHAPTER VIII . · 56 ib . 62 74 • 76 · 79 EQUILIBRIUM OF A SYSTEM OF BODIES · 13 91 CHAPTER IX . MECHANICAL POWERS • 109 ib . I. Wheel and axle II ...
Page 12
... Supports a weight on an inclined plane : sup- posing the force to act parallel to the plane and to be equal to the pressure on the plane , to find the inclination of the plane to the horizon . Let P , fig . ( 11 ) , be the force , R the ...
... Supports a weight on an inclined plane : sup- posing the force to act parallel to the plane and to be equal to the pressure on the plane , to find the inclination of the plane to the horizon . Let P , fig . ( 11 ) , be the force , R the ...
Page 17
... supported on an inclined plane , the in- clination of which to the horizon is 30 ° , first , by a power parallel to the plane , and , secondly , by a power parallel to the base : to compare the pressures on the plane in the two cases ...
... supported on an inclined plane , the in- clination of which to the horizon is 30 ° , first , by a power parallel to the plane , and , secondly , by a power parallel to the base : to compare the pressures on the plane in the two cases ...
Page 19
... supports a weight W : supposing R to be the pressure on the plane , to prove that W2 = P2 + PR + R2 . The reaction of the inclined plane against the weight is equal to R , and the angle between this reaction and P's direc- tion is equal ...
... supports a weight W : supposing R to be the pressure on the plane , to prove that W2 = P2 + PR + R2 . The reaction of the inclined plane against the weight is equal to R , and the angle between this reaction and P's direc- tion is equal ...
Page 29
... supporting weights P1 , P , P , P ; to prove that , if there is equilibrium , P P P P - G Ca = Let 0 , fig ( 29 ) , be the position of the particle ; C the centre of the square 4,4,4,4 ,: draw CM , OM , parallel to A4 , A4 , to ...
... supporting weights P1 , P , P , P ; to prove that , if there is equilibrium , P P P P - G Ca = Let 0 , fig ( 29 ) , be the position of the particle ; C the centre of the square 4,4,4,4 ,: draw CM , OM , parallel to A4 , A4 , to ...
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attached body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometry given circle given point hence highest point horizontal plane inclined plane intersection join latus rectum length lever line of quickest lowest point magnitude and direction middle point motion moveable parabola parallel particle pendulum perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles seconds SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ three forces uniform rod University of Cambridge velocity of projection vertical circle vertical plane wheel
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Page 145 - OUT of childhood into manhood Now had grown my Hiawatha, Skilled in all the craft of hunters, Learned in all the lore of old men, In all youthful sports and pastimes, In all manly arts and labors. Swift of foot was Hiawatha ; He could shoot an arrow from him, And run forward with such fleetness, That the arrow fell behind him...