 | Charles Hutton - Mathematics - 1811 - 406 pages
...PROBLEM XVII. IN a Right-angled Triangle, having given the Perimeter, or Sum of all the Sides, and the Perpendicular let fall from the Right Angle on the Hypothenuse ; to determine the Triangle, that is, its Sides. PROBLEM xvm.. . To. determine a Right-angled Triangle; having given the Hypothenuse,... | |
 | Charles Hutton - Mathematics - 1812 - 620 pages
...PROBLEM XVII. IN a Right-angled Triangle, having given the Perimeter, or Sum of all the Sides, and the Perpendicular let fall from the Right Angle on the Hypothenuse ; to determine the Triangle, that is, its Sides. PROBLEM XVIII. To determine a Right-angled Triangle ; having given the Hypothenuse,... | |
 | Charles Hutton - Mathematics - 1822 - 616 pages
...PROBLEM XVII. IN a Right-angled Triangle, having given the Perimeter or Sum of all the Sides, and the Perpendicular let fall from the Right Angle on the Hypothenuse ; to determine the Triangle, that is, its Sides. PROBLEM XVIII. To determine, a Right-angled Triangle ; having given the Hypothenuse,... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...tangent t» each other. PROBLEM XVII. In a right angled triangle, having given the perimeter and the perpendicular let fall from the right angle on the hypothenuse, to determine the triangle. PROBLEM XVIII. To determine a right angled triangle, having given the hypothenuse and the difference... | |
 | George Clinton Whitlock - Mathematics - 1848 - 340 pages
...determine the figure. 14° Given the perimeter, na, of a right angled triangle, and the perpendicular, a, let fall from the right angle on the hypothenuse, to determine the triangle. Let the segments of the hypothenuse be represented by x and y ; then shall we have Fig. 29. and —... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...tangent to each other. PROBLEM XVII.— In a right-angle triangle, having given the perimeter and the perpendicular let fall from the right angle on the hypothenuse, to determine the triangle. PROBLEM XVIII. — To determine a right-angled triangle, having given the hypothenuse and the difference... | |
 | John William Norie - Nautical astronomy - 1852 - 844 pages
...base, or greatest side, Is to the sum of the other two sides, So is the difference of those sides, To the difference of the segments made by a perpendicular let fall from the greatest angle upon the base. Then half this difference added to half the sum of the segments — that... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...tangent to each other. PROBLEM XVII. — In a right•angle triangle, having given the perimeter and the perpendicular let fall from the right angle on the hypothenuse, to determine the triangle. PROBLEM XVIII. — To determine a right•angled triangle, having given the hypothenuse and 1the difference... | |
 | Charles Davies - Algebra - 1856 - 224 pages
...finally, 3R R 1 +2 PROBLEM XVII. — In a right-angle triangle, having given the perimeter and the perpendicular let fall from the right angle on the hypothenuse, to determine the triangle. Let ACB be a right-angled triangle, right angled at C ; and let CD be drawn perpendicular to the hypothenuso... | |
 | Benjamin Greenleaf - Geometry - 1862 - 532 pages
...XVI. 709. In a right-angled triangle, having given the perimeter, or sum of all the sides, and the perpendicular let fall from the right angle on the hypothenuse, to determine the triangle, that is, its sides. PROBLEM XVII. 710. To determine a right-angled triangle, having given the hypothenuse,... | |
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PROBLEM XVII. IN a Right-angled Triangle, having given the Perimeter or Sum of all the Sides, and the Perpendicular let fall from the Right Angle on the Hypothenuse ; to determine the Triangle, that is, its Sides. PROBLEM XVIII. 
