Algebra for Beginners |
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Page 43
... less by 5 than the product of b and c . 26. Simplify - - - - 3a2 – ( 4a – b2 ) – { 2a2 — ( 3b − a2 ) – 2b – 3a } – { 5b -- 7a — ( c2 — b2 ) } . 27. Find the continued product of x2 + xy + y2 , x2 - xy + y2 , x1- x2y2 + y1 . 28. Divide ...
... less by 5 than the product of b and c . 26. Simplify - - - - 3a2 – ( 4a – b2 ) – { 2a2 — ( 3b − a2 ) – 2b – 3a } – { 5b -- 7a — ( c2 — b2 ) } . 27. Find the continued product of x2 + xy + y2 , x2 - xy + y2 , x1- x2y2 + y1 . 28. Divide ...
Page 60
... less of them is 6 ; what is the other ? 16. What number is less than 30 by y ? 17. The sum of 12 equal numbers is 48x ; what is the value of each number ? 18. How many numbers each equal to y must be taken to make 15xy ? 19. If there ...
... less of them is 6 ; what is the other ? 16. What number is less than 30 by y ? 17. The sum of 12 equal numbers is 48x ; what is the value of each number ? 18. How many numbers each equal to y must be taken to make 15xy ? 19. If there ...
Page 65
... less than A and 4 dollars more than C ? Example III . Divide 60 into two parts , so that three times the greater may exceed 100 by as much as 8 times the less falls short of 200 . Let x be the greater part , then 60 x is the less ...
... less than A and 4 dollars more than C ? Example III . Divide 60 into two parts , so that three times the greater may exceed 100 by as much as 8 times the less falls short of 200 . Let x be the greater part , then 60 x is the less ...
Page 66
... less by 1 than three times the number ; find it . 16. How much must be added to 28 so that the resulting number may be 8 times the added part ? 17. Find the number whose double exceeds its half by 9 . 18. What is the number whose ...
... less by 1 than three times the number ; find it . 16. How much must be added to 28 so that the resulting number may be 8 times the added part ? 17. Find the number whose double exceeds its half by 9 . 18. What is the number whose ...
Page 69
... less than $ 10 as the price of 27 yards exceeds $ 20 ; find the price per yard . 12. A hundredweight of tea , worth $ 68 , is made up of two sorts , part worth 80 cents a pound and the rest worth 50 cents a pound ; how much is there of ...
... less than $ 10 as the price of 27 yards exceeds $ 20 ; find the price per yard . 12. A hundredweight of tea , worth $ 68 , is made up of two sorts , part worth 80 cents a pound and the rest worth 50 cents a pound ; how much is there of ...
Common terms and phrases
a²+b² acres algebraical sum Arithmetic arranged beginner cents CHAPTER coefficient Completing the square compound expressions convenient cube root descending powers difference digits dimes Divide division divisor Elementary Algebra equal examples see Elementary EXAMPLES XVII exceeds Find the highest Find the lowest find the number Find the product Find the square Find the sum find the value following expressions given expressions half-dollars Hence highest common factor lowest common denominator lowest common multiple lowest terms miles an hour miles per hour minute-hand Multiply negative numerator and denominator obtain quadratic equation quotient Reduce to lowest remainder removing brackets Resolve into factors result rule of signs side simple equation simultaneous equations Solve the equations square root Subtract Transposing trinomial unknown quantities walk whence write yards α α
Popular passages
Page 91 - The product is a2+2a6-}-62; from which it appears, that the square of the sum of two quantities, is equal to the square of the first plus twice the product of the first by the second, plus the square of the second.
Page 107 - Conversely, the difference of the squares of any two quantities is equal to the product of the sum and the difference of the two quantities.
Page 89 - It is evident from the Rule of Signs that (1) no even power of any quantity can be negative; (2) any odd power of a quantity will have the same sign as the quantity itself. NOTE. It is especially worthy of notice that the square of every expression, whether positive or negative, is positive.
Page 54 - Transpose all the terms containing the unknown quantity to one side of the equation, and the "known quantities to the other.