A Treatise on Statics: Containing the Theory of the Equilibrium of Forces; and Numerous Examples Illustrative of the General Principles of the Science |
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Page 20
... resolved into their original components ; viz . , m into f and F , acting at Pin the directions Pf and PR ; ( PR being drawn parallel to AF ) ; and n into f ' and F ' acting at P in the directions Pf and PR , which is also parallel to ...
... resolved into their original components ; viz . , m into f and F , acting at Pin the directions Pf and PR ; ( PR being drawn parallel to AF ) ; and n into f ' and F ' acting at P in the directions Pf and PR , which is also parallel to ...
Page 39
... resolved into two components , one perpendicular and the other parallel to the given line ; the moment of the former will be found by the definition just given , and that of the latter will be zero . 76. According to this definition Z1y ...
... resolved into two components , one perpendicular and the other parallel to the given line ; the moment of the former will be found by the definition just given , and that of the latter will be zero . 76. According to this definition Z1y ...
Page 49
... resolved parts of the forces parallel to any three lines at right angles to each other must be separately equal to zero . And , the sums of the moments of the forces , about any three lines at right angles to each other and passing ...
... resolved parts of the forces parallel to any three lines at right angles to each other must be separately equal to zero . And , the sums of the moments of the forces , about any three lines at right angles to each other and passing ...
Page 51
... resolved parts of ΣΧ , ΣΥ along this plane may be equal and in contrary directions . Let a normal to this plane make an angle e with EX , and therefore an angle 90 ° – 0 with ΣΥ ; then the components ΣΧ.cos 0 parallel to the normal , of ...
... resolved parts of ΣΧ , ΣΥ along this plane may be equal and in contrary directions . Let a normal to this plane make an angle e with EX , and therefore an angle 90 ° – 0 with ΣΥ ; then the components ΣΧ.cos 0 parallel to the normal , of ...
Page 52
... resolved into its components ΣΧ , ΣΥ , ΣΖ , the first two acting in directions in which the line cannot move produce no effect ; but ΣΖ acting in the direction in which the line can move must be equal to zero if there be equilibrium ...
... resolved into its components ΣΧ , ΣΥ , ΣΖ , the first two acting in directions in which the line cannot move produce no effect ; but ΣΖ acting in the direction in which the line can move must be equal to zero if there be equilibrium ...
Common terms and phrases
a₁ axle balance beam Cambridge catenary centre of gravity College components conditions of equilibrium consequently cos² curve cylinder density direction distance draw dx)² equal to zero equation equi exerts F₁ F₂ find the centre find the conditions find the position fixed axis fixed point forces acting forces F forces which act friction frustum fulcrum Hence horizontal plane inclined plane John Deighton length lever librium m₁ machine magnitude motion parallelogram particle passing perpendicular position of equilibrium pressure proportional pulley pyramid radius represent resolved respectively rest resultant couple right angles rigid body screw shew single force smooth string suppose surface suspended Taylor's theorem tension three forces transposed triangle Trinity College University of Cambridge virtual velocities wheel Wherefore ΣΖ ΣΥ ΣΧ
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