Units and Physical Constants |
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Page 1
... Hence the inch is 2.5399772 centimetres . Area . 1 sq . inch , 1 sq . foot , 1 sq . yard , 1 sq . mile , sq . cm . 6.4516 929.01 = 8361.13 2.59 x 1010 Reciprocals . • 1550 ⚫001076 0001196 3.861 x 10-11 A Volume . cub . cm . Reciprocals ...
... Hence the inch is 2.5399772 centimetres . Area . 1 sq . inch , 1 sq . foot , 1 sq . yard , 1 sq . mile , sq . cm . 6.4516 929.01 = 8361.13 2.59 x 1010 Reciprocals . • 1550 ⚫001076 0001196 3.861 x 10-11 A Volume . cub . cm . Reciprocals ...
Page 2
... Hence the kilogramme would be 2-2046212 pounds , and the pound 453.59265 grammes . Three standard pounds , one of platinum - iridium and the other two of gilded bronze , belonging to the Standards Department , were compared , in 1883 ...
... Hence the kilogramme would be 2-2046212 pounds , and the pound 453.59265 grammes . Three standard pounds , one of platinum - iridium and the other two of gilded bronze , belonging to the Standards Department , were compared , in 1883 ...
Page 7
... hence we must have V Lt = v 7 T ( 1 ) This equation shows that , when the units are changed ( a change which does not affect V , L , and T ) , v must vary directly as l and inversely as t ; that is to say , the unit of velocity varies ...
... hence we must have V Lt = v 7 T ( 1 ) This equation shows that , when the units are changed ( a change which does not affect V , L , and T ) , v must vary directly as l and inversely as t ; that is to say , the unit of velocity varies ...
Page 11
... Hence in ordinary division either the divisor is a mere numerical quantity and the quotient a quantity of the same nature as the dividend ; or else the divisor is of the same nature as the dividend , and the quotient a mere numerical ...
... Hence in ordinary division either the divisor is a mere numerical quantity and the quotient a quantity of the same nature as the dividend ; or else the divisor is of the same nature as the dividend , and the quotient a mere numerical ...
Page 13
... Hence by division 1 74 = ( ft . ) 4 , 7 = ft . = 4 in . 81 Ex . 3. If the area of a field of 10 acres be represented by 100 , and the acceleration of gravity ( taken as 32 foot- second units ) be 583 , find the unit of time . We have ...
... Hence by division 1 74 = ( ft . ) 4 , 7 = ft . = 4 in . 81 Ex . 3. If the area of a field of 10 acres be represented by 100 , and the acceleration of gravity ( taken as 32 foot- second units ) be 583 , find the unit of time . We have ...
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acceleration ARITHMETIC body C.G.S. system C.G.S. units Cambridge Carbonic Acid cell cent centimetre Chemistry College column compression Copper Crown 8vo cubic centim denote density dimensions distance dynes dynes per square earth's electromotive force electrostatic unit ELEMENTARY TREATISE equal equation equivalent ergs farad Fcap following values formula fundamental units given Globe 8vo grammes gravity Hence Hydrogen inch index of refraction intensity Iron liquid LL.D magnetic Mathematics measure mercury metre millimetre multiplied Nature Series nitric acid numerical value numerous Illustrations Owens College Peltier effect physical Platinum pressure PRIMER Professor quantity of electricity quotient radius ratio refraction Regnault Second Edition shear Silver solid specific heat specific resistance specimen square centim standard stress substance sulphate surface Temp temperature thermal capacity thermoelectric thermoelectric heights Thomson effect tion unit mass unit of length vacuo value of g velocity volume wire Young's modulus Zinc zinc sulphate
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