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17. Expand (√1−x2+1)5—(√1−x2−1)5.

18. Find the coefficient of x12 in (x2+2x)10.

19. Find the coefficient of x in x2

α 14 2x

20. Find the term independent of x in (2x2.
(2x2 – 1) 13.

21. Find the coefficient of x-20 in

x2

2 15

3

389. In the expansion of (1+x)" the coefficients of terms equidistant from the beginning and end are equal.

The coefficient of the (r+1)th term from the beginning is nCr

The (r+1)th term from the end has n+1-(r+1), or n−r terms before it; therefore counting from the beginning it is the (n-r+1)th term, and its coefficient is "Cn-r, which has been shown to be equal to "C, [Art. 370.] Hence the proposition. follows.

390.

Greatest coefficient. in the expansion of (1+x)".

To find the greatest coefficient

The coefficient of the general term of (1+x)" is "C,; and we have only to find for what value of r this is greatest.

By Art. 375, when ʼn is even, the greatest coefficient is "C1;

when ʼn is odd, it is "Cn-1, or "Cn+1; these coefficients being equal.

391. Greatest term.

of (x+a)".

2

To find the greatest term in the expansion

(x+a)"=x" (1+2)";
(1+)",

We have

therefore, since " multiplies every term in

a

it will be

sufficient to find the greatest term in this latter expansion.

Let the 7th and (r+1)th be any two consecutive terms. The (r+1)th term is obtained by multiplying the rth term by n-r+1 a

a

; that is, by ("+1-1).

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r

[Art. 384.]

2+1

The factor

r

1 decreases as increases; hence the (+1)th term is not always greater than the 7th term, but only

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(1).

be an integer, denote it by p; then if r=

=p the

multiplying factor becomes 1, and the (p+1)th term is equal to the pth; and these are greater than any other term.

If

(2+1) a be not an integer, denote its integral part by q;

x + a

then the greatest value of r consistent with (1) is q; hence the (q+1)th term is the greatest.

Since we are only concerned with the numerically greatest term, the investigation will be the same for (x-a)"; therefore in any numerical example it is unnecessary to consider the sign of the second term of the binomial. Also it will be found best to work each example independently of the general formula.

Example. Find the greatest term in the expansion of (1+4x)3, 1 when x has the value

3'

Denote the 7th and (r+1)th terms by T, and T+1 respectively; then

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The greatest value of r consistent with this is 5; hence the greatest term is the sixth, and its value

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392. To find the sum of the coefficients in the expansion of (1+x)".

In the identity (1+x)=1+С1x+Сqx2+Сzx3+...+Cnx,

=1; thus

put x=

COR.

2=1+C1+C2+Cg+...+Cn

=sum of the coefficients.

C1+ C2+C3+...+C12=2"-1;

that is, the total number of combinations of n things taking some or all of them at a time is 2" — 1.

393. To prove that in the expansion of (1+x)", the sum of the coefficients of the odd terms is equal to the sum of the coefficients of

the even terms.

In the identity (1+x)=1+С1x+Сqx2+Cgx3+...+C,

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394. The Binomial Theorem may also be applied to expand expressions which contain more than two terms.

Example. Find the expansion of (x2 + 2x − 1)3.
Regarding 2x-1 as a single term, the expansion

=(x2)3+3(x2)2 (2x − 1) + 3x2 (2x − 1)2 + (2x − 1)3

=x6 +6x2 + 9x1 – 4x3 – 9x2 + 6x – 1, on reduction.

395. For a full discussion of the Binomial Theorem when the index is not restricted to positive integral values the student is referred to Chap. XLVII. It is there shown that when x is less than unity, the formula

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When n is negative or fractional the number of terms in the expansion is unlimited, but in any particular case we may write down as many terms as we please, or we may find the coefficient of any assigned term.

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396. In finding the general term we must now use the formula

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written in full; for the symbol "C, cannot be employed when n is fractional or negative.

1

Example 1. Find the general term in the expansion of (1+x)2.

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The number of factors in the numerator is r, and r-1 of these are negative; therefore, by taking –1 out of each of these negative factors, we may write the above expression

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Example 2. Find the general term in the expansion of (1 − x)−3.

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by removing like factors from the numerator and denominator.

397. The following example illustrates a useful application of the Binomial Theorem.

Example. Find the cube root of 126 to 5 places of decimals,

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In the following expansions find which is the greatest term:

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