Elementary Algebra |
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Page 49
... show . Subtract x from both sides of the equation , and we get 3x - x - 8 = 12 ......... Adding 8 to both sides , we have 3x - x = 12 + 8 ..... ( Axiom 2 ) . ... ( Axiom 1 ) . Thus we see that + x has been removed from one side , and ...
... show . Subtract x from both sides of the equation , and we get 3x - x - 8 = 12 ......... Adding 8 to both sides , we have 3x - x = 12 + 8 ..... ( Axiom 2 ) . ... ( Axiom 1 ) . Thus we see that + x has been removed from one side , and ...
Page 51
... show that when we substitute the value of x in the two sides of the equa- tion we obtain the same result . Example . To show that x = 2 satisfies the equation 5x − ( 4x —7 ) ( 3x - 5 ) = 6−3 ( 4x − 9 ) ( x − 1 ) ............ ..Ex ...
... show that when we substitute the value of x in the two sides of the equa- tion we obtain the same result . Example . To show that x = 2 satisfies the equation 5x − ( 4x —7 ) ( 3x - 5 ) = 6−3 ( 4x − 9 ) ( x − 1 ) ............ ..Ex ...
Page 85
... show that E is a common factor of A and B. By examining the steps of the work , it is clear that E divides D , therefore also qD ; therefore qD + E , therefore nA ; therefore 4 , since n is a simple factor . Again , E divides D ...
... show that E is a common factor of A and B. By examining the steps of the work , it is clear that E divides D , therefore also qD ; therefore qD + E , therefore nA ; therefore 4 , since n is a simple factor . Again , E divides D ...
Page 90
... show that the lowest common multiple is the product of the three quantities divided by the square of the highest common factor . 11. Find the lowest common multiple of x1 + ax3 + a3x + a1 , ¿ c1 + a2x2 + aa . 12. Find the highest common ...
... show that the lowest common multiple is the product of the three quantities divided by the square of the highest common factor . 11. Find the lowest common multiple of x1 + ax3 + a3x + a1 , ¿ c1 + a2x2 + aa . 12. Find the highest common ...
Page 116
... show how complex fractions can be reduced by the rules already given . Example 1 . a + b a с C - a a ( 3 + 1 ) + ( − 9 ) b ad + bc ad - bc Example 2 . x + x = = bd bd ad + bc bd X bd ad - bc ad + bc = ad - bc х = ི | ། ။ - = x x + DC ...
... show how complex fractions can be reduced by the rules already given . Example 1 . a + b a с C - a a ( 3 + 1 ) + ( − 9 ) b ad + bc ad - bc Example 2 . x + x = = bd bd ad + bc bd X bd ad - bc ad + bc = ad - bc х = ི | ། ။ - = x x + DC ...
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Common terms and phrases
a+3b a+b+c a₁ a²+b² arithmetic means arithmetical arranged ascending powers b₁ beginner Binomial Theorem cents CHAPTER coefficients column compound expression continued fraction convergent cube root decimal denote digits dimes Divide dividend division divisor equal EXAMPLES XI Find the highest find the number Find the square Find the sum find the value following expressions given expressions greater harmonic mean Hence highest common factor integer less letters logarithm lowest common multiple method miles an hour Multiply number of terms numerator and denominator obtain partial fractions prefixed prove quadratic quadratic equation quotient ratio remainder Resolve into factors result rule of signs second term Simplify SIMULTANEOUS EQUATIONS solution square root subtraction Suppose surds symbols Transposing unknown quantity walk whence write yards zero
Popular passages
Page 331 - The logarithm of a product is equal to the sum of the logarithms of its factors.
Page 256 - In a quadratic equation wJiere the coefficient of the first term is unity, (i) the sum of the roots is equal to the coefficient of x with its sign changed ; (ii) the product of the roots is equal to the third term.
Page 168 - Thus the 4th root (2x2) = the square root of the square root ; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root.
Page 178 - A basket of oranges is emptied by one person taking half of them and one more, a second person taking half of the remainder and one more, and a third person taking half of the remainder and six more. How many did the basket contain at first ? 17.
Page 179 - Two vessels contain mixtures of wine and water ; in one there is three times as much wine as water, in the other five times as much water as wine. Find how much must be drawn off from each to fill a third vessel which holds seven gallons, in order that its contents may be half wine and half water.
Page 280 - The pressure of wind on a plane surface varies jointly as the area of the surface, and the square of the wind's velocity. The pressure on a square foot is 1...
Page 213 - Art. 167 we saw that if the number of unknown quantities is greater than the number of independent equations, there will be an unlimited number of solutions, and the equations will be indeterminate. By introducing conditions, however, we can limit the number of solutions. When positive integral values of the unknown quantities are required, the equations are called simple indeterminate equations. The introduction of this restriction enables us to express the solutions in a very simple form. Ex. 1....