Page images
PDF
EPUB

47. Example 8. Divide .01265 by .55.

Log. of .01265 = 2.1020905

Log. of.55 1.7403627

=

Log. of .023 = 2.3617278

CHA P. IV.

Of the APPLICATION of LOGARITHMS to CIRCULATING DECIMALS.

48.

A

S in fome Calculations, in which we propose to be very accurate, we may have Occafion to find the Logarithms of circulating Decimals; we shall explain the Method by which they may be found, as follows.

The RULE. First turn the circulating Decimal into its equivalent vulgar Fraction, (as fhewn in Theorems 4, 5, 6, and 7, in Articles 13, 14, 15, 16, 17, 18, 19, 20, and 21, of the Effay on Circulating Decimals,) and then find the Logarithm of that vulgar Fraction, by Art. 21 of this ESSAY.

49. Example 1. What is the Logarithm of .4? By Art. 14. of the Effay on Circulating Decimals, •4 = $.

Hence from Log. of 40.6020600

Subtract Log. of 90.9542425

Gives Log. of or of .4 1.6478175

50. Example 2. What is the Logarithm of 3.5 ? Solution. By Art. 16 of the Effay on Circulating Decimals, 3.5.

From Log. of 350 = 2.5440680
Subtract Log. of 99 = 1.9956352

[blocks in formation]

51. Example 3. What is the Logarithm of .23? Solution. By Art. 18 of the Essay on Circulating

1

Decimals, .23 = 25.

From Log. of 21 = 1.3222193
Subtract Log. of 90 = 1.9542425

[blocks in formation]

52. Example 4. What is the Log. of 26353.5?

Solution. By Art. 20 of the Essay on Circulating

[blocks in formation]

Therefore, from Log. of 2609000 = 6.4164741 Subtract the Log. of 99

1.9956352

The Remainder is the Log. of 2609000 4.4208389

99

53. The Logarithms of Circulating Decimals being found by the above Method; Multiplication, and Divifion, are performed by them, after the fame Manner as is fhewn of finite Numbers in Chap. 2. and 3. of this ESSAY.

CHAP

CHAP.

V.

The GOLDEN RULE by LOGARITHMS.

54.

FL

ROM the Nature of the Golden Rule, and Logarithms, we have this Rule. Add the Logarithms of the fecond and third Terms together; from their Sum fubtract the Logarithm of the first Term; and the Remainder will be the Logarithm of the fourth, or required Term.

55. Suppofe in the Rule of Three Direct we have this Stating, As 4.1: 5: 65 a fourth Number..

[ocr errors]
[blocks in formation]

55. If from the Logarithm of 1 be fubtracted the Logarithm of any Number, the Remainder is called the Arithmetical Complement of that Logarithm. Hence, the Arithmetical Complement of the Logarithm of any Number, is equal to the Logarithm of the Quotient of I divided by that Number.

56. When it is required to divide one Number by another, it is in Effect the fame, if we divide by the Divifor, and multiply that Quotient by the given

a

I

Dividend. (For = X a.) Which is done by

m. 112

Logarithms, by adding the Logarithm of the Dividend to the Arithmetical Complement of the Logarithm of the Divifor.

57. Hence, the Operation of the Example in Art. 55, may ftand thus:

From

From Log. of 1 = 0.0000000

Sub. Log. of 4.1

0.6127839

Gives Arith, Comp. = 1.3872161

1.3872161

: 0.6989700 1.8129134

[merged small][ocr errors][merged small][merged small]

58.

[ocr errors]

O raife any Number to a given Power by Logarithms, multiply the Logarithm of the Root by the Index of the given Power. Thus, for Inftance, if we are to fquare any Number, we muft multiply its Logarithm by 2; if to cube a Number, by 3, &c. and the Product (by Art. 4.) will be the Logarithm of the required Power.

Note, If the Root be a Fraction, its Logarithm will be a Binomial; in fuch Cafe, the Carriage from the decimal Part in multiplying being affirmative, and the Product of the Charactcriftick negative, the Carriage must be subtracted from that negative Product, for the required negative Characteristick. 59. Example 1. What is the Square of 15? Log. of 15 1.1760913

2

Log. of 225 2.3521826

60. Example 2. Cube .55.

Log. of .55 = 1.7403627

3

Log. of .166375 = 1.2210881

CHAP.

تية

« PreviousContinue »