A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 3
... chords passing through the point ; if the position of one of the chords and the direction of the resultant be given , to determine the positions of the other chord . Let BAC , fig . ( 5 ) , be the curve ; let the chord AP , given in ...
... chords passing through the point ; if the position of one of the chords and the direction of the resultant be given , to determine the positions of the other chord . Let BAC , fig . ( 5 ) , be the curve ; let the chord AP , given in ...
Page 19
... chords PA , PB ; shew that , if PC be a diameter of the circle , the tensions of the strings are in the ratio of BC to AC . SECT . 3. Each force equal and opposite to the resultant of the other two . If three forces act on a point , it ...
... chords PA , PB ; shew that , if PC be a diameter of the circle , the tensions of the strings are in the ratio of BC to AC . SECT . 3. Each force equal and opposite to the resultant of the other two . If three forces act on a point , it ...
Page 22
... chords in a circle , and P is a point on the circumference , half way between A and B : prove that if forces , represented by the lines PA , PB , PC , PD , act at the point P , their resultant is constant . ( 6 ) Forces are applied at ...
... chords in a circle , and P is a point on the circumference , half way between A and B : prove that if forces , represented by the lines PA , PB , PC , PD , act at the point P , their resultant is constant . ( 6 ) Forces are applied at ...
Page 72
... chord joining the two im- moveable weights . " ( 31 ) If P1 Pa P1 , be the perpendicular distances , from the sides , of the centre of gravity of the portion of a triangle remain- ing , after the part within the inscribed circle is ...
... chord joining the two im- moveable weights . " ( 31 ) If P1 Pa P1 , be the perpendicular distances , from the sides , of the centre of gravity of the portion of a triangle remain- ing , after the part within the inscribed circle is ...
Page 138
... chord of the parabolic path is pro- portional to the product of the velocities of the body at the two points . - = = Let P , P ' , fig . ( 105 ) , be the ends of any focal chord PSP ' : draw PH , P'H ' , SK , vertically , to meet the ...
... chord of the parabolic path is pro- portional to the product of the velocities of the body at the two points . - = = Let P , P ' , fig . ( 105 ) , be the ends of any focal chord PSP ' : draw PH , P'H ' , SK , vertically , to meet the ...
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos˛ cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin˛ sliding smooth sphere straight line string passing supposing suspended tanš tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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