A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page ix
... Geometrical method • • 25 ib . II . Components along two lines at right angles to each other III . Components along any two lines not parallel IV . Friction 26 • 35 " ib . CHAPTER V. SECTION PAGE EQUILIBRIUM OF A BODY MOVEABLE ABOUT.
... Geometrical method • • 25 ib . II . Components along two lines at right angles to each other III . Components along any two lines not parallel IV . Friction 26 • 35 " ib . CHAPTER V. SECTION PAGE EQUILIBRIUM OF A BODY MOVEABLE ABOUT.
Page 35
... Friction . ( 1 ) If the roughness of a plane , which is inclined to the horizon at a known angle , be such that a ... friction . Then , resolving forces along and OF FORCES ACTING ON A POINT . 35 Components along any two lines not ...
... Friction . ( 1 ) If the roughness of a plane , which is inclined to the horizon at a known angle , be such that a ... friction . Then , resolving forces along and OF FORCES ACTING ON A POINT . 35 Components along any two lines not ...
Page 36
... friction and a the inclination of the plane . The forces producing equilibrium in the two cases are exhibited in the figures ( 36 ) and ( 37 ) . For equilibrium , in the first case , we have , resolving forces parallel and ...
... friction and a the inclination of the plane . The forces producing equilibrium in the two cases are exhibited in the figures ( 36 ) and ( 37 ) . For equilibrium , in the first case , we have , resolving forces parallel and ...
Page 37
... friction , and R ' , R " , the values of R when λ is equal + μ , the extreme limits of the value of X , 1 R ' and therefore = COS € μ sin € 1 --- W cos ( a + e ) ' R " 1 1 R ' + R " = = - = μ , respectively , which are cos e + μ sin € W ...
... friction , and R ' , R " , the values of R when λ is equal + μ , the extreme limits of the value of X , 1 R ' and therefore = COS € μ sin € 1 --- W cos ( a + e ) ' R " 1 1 R ' + R " = = - = μ , respectively , which are cos e + μ sin € W ...
Page 38
... friction . If a be the inclination of the plane to the horizon , the co- efficient of friction is equal to tan a . tan2 a 2 ' ( 8 ) A body is just supported on a rough inclined plane by a force acting along it ; find the angle between ...
... friction . If a be the inclination of the plane to the horizon , the co- efficient of friction is equal to tan a . tan2 a 2 ' ( 8 ) A body is just supported on a rough inclined plane by a force acting along it ; find the angle between ...
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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