A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page ix
... opposite to the resultant of the other two 19 ib . 15 CHAPTER III . RESULTANT OF ANY NUMBER OF FORCES ACTING ON A POINT I. Geometrical method II . Trigonometrical method CHAPTER IV . • 21 ib . 23 EQUILIBRIUM OF ANY NUMBER OF FORCES ...
... opposite to the resultant of the other two 19 ib . 15 CHAPTER III . RESULTANT OF ANY NUMBER OF FORCES ACTING ON A POINT I. Geometrical method II . Trigonometrical method CHAPTER IV . • 21 ib . 23 EQUILIBRIUM OF ANY NUMBER OF FORCES ...
Page 3
... opposite sides of a quadrilateral in a circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be ...
... opposite sides of a quadrilateral in a circle , towards the same parts , and are respectively proportional to these sides : to prove that the resultant will pass through the intersection of the diagonals . Let ABCD , fig . ( 6 ) , be ...
Page 4
... angles to each other , shew how the lines representing the forces may be found by a geometrical construc- tion . ( 10 ) Two forces act along opposite sides of 4 RESULTANT OF TWO FORCES ACTING ON A POINT . SECTION PAGE SECTION PAGE.
... angles to each other , shew how the lines representing the forces may be found by a geometrical construc- tion . ( 10 ) Two forces act along opposite sides of 4 RESULTANT OF TWO FORCES ACTING ON A POINT . SECTION PAGE SECTION PAGE.
Page 5
William Walton. ( 10 ) Two forces act along opposite sides of a quadri- lateral in a circle , towards opposite parts , and are respectively proportional to these sides ; prove that their resultant passes through the intersection of the ...
William Walton. ( 10 ) Two forces act along opposite sides of a quadri- lateral in a circle , towards opposite parts , and are respectively proportional to these sides ; prove that their resultant passes through the intersection of the ...
Page 13
... perpendiculars drawn from the angles of a triangle to the opposite sides , and their magnitudes inversely proportional to these perpendiculars : to prove that the three EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 13.
... perpendiculars drawn from the angles of a triangle to the opposite sides , and their magnitudes inversely proportional to these perpendiculars : to prove that the three EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 13.
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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