A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 4
... perpendicular erected at the middle point of the given straight line . ( 8 ) If ABC be a right - angled triangle and ABDE , ACFG , be the squares on the sides , constructed as in Euclid I. 47 ; prove that the resultant of forces ...
... perpendicular erected at the middle point of the given straight line . ( 8 ) If ABC be a right - angled triangle and ABDE , ACFG , be the squares on the sides , constructed as in Euclid I. 47 ; prove that the resultant of forces ...
Page 10
... perpendicular to each other and are in the ratio of 3 to 4 , is equivalent to a weight of 60 pounds : to deter- mine the forces . The required forces are equivalent to weights of 36 and 48 pounds . ( 27 ) The resultant of two forces ...
... perpendicular to each other and are in the ratio of 3 to 4 , is equivalent to a weight of 60 pounds : to deter- mine the forces . The required forces are equivalent to weights of 36 and 48 pounds . ( 27 ) The resultant of two forces ...
Page 26
... forces in the line AC , and another in the perpendicular line BD : hence T = P . Again , the pressure on either of the higher tacks 26 EQUILIBRIUM OF ANY NUMBER OF Components along two lines at right angles to each other.
... forces in the line AC , and another in the perpendicular line BD : hence T = P . Again , the pressure on either of the higher tacks 26 EQUILIBRIUM OF ANY NUMBER OF Components along two lines at right angles to each other.
Page 39
... perpendicular and inclined at an angle ẞ to the intersection of the inclined plane with a horizontal plane : the weights are in equilibrium , the former being only just supported : prove that , μ , μ ' , being the respective ...
... perpendicular and inclined at an angle ẞ to the intersection of the inclined plane with a horizontal plane : the weights are in equilibrium , the former being only just supported : prove that , μ , μ ' , being the respective ...
Page 47
... perpendicular distance of the fulcrum from the direction of either weight be one inch , find the lengths of the arms . The lengths of the arms in inches are √5 and √5 . ( 25 ) One end of a uniform beam is placed on the ground against ...
... perpendicular distance of the fulcrum from the direction of either weight be one inch , find the lengths of the arms . The lengths of the arms in inches are √5 and √5 . ( 25 ) One end of a uniform beam is placed on the ground against ...
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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Page 255 - THIS series is intended to supply for the use of Schools and Students cheap and accurate editions of the Classics, which shall be superior in mechanical execution to the small German editions now current in this country, and more convenient in form. The texts of the " Bibliotheca Classica" and " GrammarSchool Classics,'" so far as they have been published, will be adopted.