A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Results 1-5 of 35
Page 9
... at an angle of 90 ° : to compare the magnitudes of the resultants in the two cases . The ratio of the former to the latter resultant is equal to W. S. ( 1 + 1 ) 2 ( 22 ) Two equal forces P , P , RESULTANT OF TWO FORCES ACTING ON A POINT .
... at an angle of 90 ° : to compare the magnitudes of the resultants in the two cases . The ratio of the former to the latter resultant is equal to W. S. ( 1 + 1 ) 2 ( 22 ) Two equal forces P , P , RESULTANT OF TWO FORCES ACTING ON A POINT .
Page 10
... ratio is equal to √ / 2 1 + tan - a : to compare the resultants ( 23 ) If the resultant of two equal forces P , P , acting on a point at an angle a , be n times as great as if the angle were 2a , to find the value of a . The value of a ...
... ratio is equal to √ / 2 1 + tan - a : to compare the resultants ( 23 ) If the resultant of two equal forces P , P , acting on a point at an angle a , be n times as great as if the angle were 2a , to find the value of a . The value of a ...
Page 12
... ratio 5 : 3 : 2 , acting on a point in any manner , keep it at rest ? or forces in the ratio 10 : 6 : 3 ? If three forces acting on a point produce equilibrium , they must generally be proportional to the three sides of a triangle . Now ...
... ratio 5 : 3 : 2 , acting on a point in any manner , keep it at rest ? or forces in the ratio 10 : 6 : 3 ? If three forces acting on a point produce equilibrium , they must generally be proportional to the three sides of a triangle . Now ...
Page 13
... ratios to the other force . Let the three forces be represented by 5P , 3P , nP : then , since the triangle is right - angled , and since its sides are propor- tional to the forces , ( 5P ) 2 = ( 3P ) 2 + ( nP ) ” , 25 = 9 + n2 , n2 ...
... ratios to the other force . Let the three forces be represented by 5P , 3P , nP : then , since the triangle is right - angled , and since its sides are propor- tional to the forces , ( 5P ) 2 = ( 3P ) 2 + ( nP ) ” , 25 = 9 + n2 , n2 ...
Page 19
... ratio of BC to AC . SECT . 3. Each force equal and opposite to the resultant of the other two . If three forces act on a point , it is sufficient and necessary for equilibrium , that any one of them be equal and opposite to the ...
... ratio of BC to AC . SECT . 3. Each force equal and opposite to the resultant of the other two . If three forces act on a point , it is sufficient and necessary for equilibrium , that any one of them be equal and opposite to the ...
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body is projected centre of gravity chord coefficient of friction collision component cosē cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum given circle given point hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle pendulum perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sinē sliding smooth sphere straight line string passing supposing suspended tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane wheel
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Page 255 - Classics, so far as they have been published, will be adopted. These editions have taken their place amongst scholars as valuable contributions to the Classical Literature of this country, and are admitted to be good examples of the judicious and practical nature of English scholarship ; and as the editors have formed their texts from a careful examination of the best editions extant, it is believed that no texts better for general use can be found. The volumes will be well printed at the Cambridge...
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