A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 17
... move- able loop O , which is capable of sliding along AOP : to find the inclination of BO to the horizon , when there is equilibrium . W. S. 3 If AB - a , BO = b , and EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 17 ERRATUM Page 73, ...
... move- able loop O , which is capable of sliding along AOP : to find the inclination of BO to the horizon , when there is equilibrium . W. S. 3 If AB - a , BO = b , and EQUILIBRIUM OF THREE FORCES ACTING ON A POINT . 17 ERRATUM Page 73, ...
Page 18
... sliding freely on the string , hangs in equilibrium : shew that , if AB = a , the weight divides the string into two parts equal to ± a sin a ( c2 - a2 cos2 a ) * ) ( 10 ) A string AHKB is attached to two fixed points A , B , in a ...
... sliding freely on the string , hangs in equilibrium : shew that , if AB = a , the weight divides the string into two parts equal to ± a sin a ( c2 - a2 cos2 a ) * ) ( 10 ) A string AHKB is attached to two fixed points A , B , in a ...
Page 19
... sliding upon it is in equilibrium when acted on by two strings in the direction of the chords PA , PB ; shew that , if PC be a diameter of the circle , the tensions of the strings are in the ratio of BC to AC . SECT . 3. Each force ...
... sliding upon it is in equilibrium when acted on by two strings in the direction of the chords PA , PB ; shew that , if PC be a diameter of the circle , the tensions of the strings are in the ratio of BC to AC . SECT . 3. Each force ...
Page 27
... sliding on the cord , sustains a given weight : to find the tension of the cord . Let A , B , fig . ( 27 ) , be the two given points , ACB the cord in a position of rest : draw CH vertically to meet the horizontal line AB in H. Let W ...
... sliding on the cord , sustains a given weight : to find the tension of the cord . Let A , B , fig . ( 27 ) , be the two given points , ACB the cord in a position of rest : draw CH vertically to meet the horizontal line AB in H. Let W ...
Page 74
... sliding being prevented by a small peg at C : to find the inclination of the plane in order that the lamina may just not topple over . Supposing the lamina to be just on the point of toppling over , the centre of gravity must be ...
... sliding being prevented by a small peg at C : to find the inclination of the plane in order that the lamina may just not topple over . Supposing the lamina to be just on the point of toppling over , the centre of gravity must be ...
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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