A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 14
... smooth vertical circle ; a string passes through both rings and hangs below the arc , three equal weights being attached to it , one at each end and one on the portion between the rings ; to find the position of the rings when they are ...
... smooth vertical circle ; a string passes through both rings and hangs below the arc , three equal weights being attached to it , one at each end and one on the portion between the rings ; to find the position of the rings when they are ...
Page 18
... prove that , when there is equilibrium , P Q R cos A 2 B C : COS : Cos 2 where A , B , C , are the angles of the triangle . ( 13 ) A smooth circular ring is fixed in 18 EQUILIBRIUM OF THREE FORCES ACTING ON A POINT .
... prove that , when there is equilibrium , P Q R cos A 2 B C : COS : Cos 2 where A , B , C , are the angles of the triangle . ( 13 ) A smooth circular ring is fixed in 18 EQUILIBRIUM OF THREE FORCES ACTING ON A POINT .
Page 19
William Walton. ( 13 ) A smooth circular ring is fixed in a horizontal position , and a small ring P sliding upon it is in equilibrium when acted on by two strings in the direction of the chords PA , PB ; shew that , if PC be a diameter ...
William Walton. ( 13 ) A smooth circular ring is fixed in a horizontal position , and a small ring P sliding upon it is in equilibrium when acted on by two strings in the direction of the chords PA , PB ; shew that , if PC be a diameter ...
Page 20
... smooth pegs A and B : a weight Wis suspended from a point 0 at a point of the string between the pegs to find W in terms of P and Q in order that the angle AOB may be a right angle . The weight W is given by the relation W2 = P2 + Q2 ...
... smooth pegs A and B : a weight Wis suspended from a point 0 at a point of the string between the pegs to find W in terms of P and Q in order that the angle AOB may be a right angle . The weight W is given by the relation W2 = P2 + Q2 ...
Page 27
... smooth ring , sliding on the cord , sustains a given weight : to find the tension of the cord . Let A , B , fig . ( 27 ) , be the two given points , ACB the cord in a position of rest : draw CH vertically to meet the horizontal line AB ...
... smooth ring , sliding on the cord , sustains a given weight : to find the tension of the cord . Let A , B , fig . ( 27 ) , be the two given points , ACB the cord in a position of rest : draw CH vertically to meet the horizontal line AB ...
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body is projected centre of gravity chord coefficient of friction collision component cosē cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum given circle given point hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle pendulum perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sinē sliding smooth sphere straight line string passing supposing suspended tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane wheel
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