A Collection of Problems in Illustration of the Principles of Elementary Mechanics |
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Page 15
... suspended : to compare the tensions of the two strings 40 , BO , a and B being their inclinations to the horizon . Since OAB = a and OBA = B , it follows that hence 2 < AOW = ¿ π + α , and ‹ BOW = 1π + ß : ST : sin < BOW : sin AOW ...
... suspended : to compare the tensions of the two strings 40 , BO , a and B being their inclinations to the horizon . Since OAB = a and OBA = B , it follows that hence 2 < AOW = ¿ π + α , and ‹ BOW = 1π + ß : ST : sin < BOW : sin AOW ...
Page 18
... suspended equal weights P , P : to find the tensions of the several portions of the string , supposing AH , HK , KB , to be all equal . If AB = c , and 7 = the whole length of the string , the ten- sion of HK is equal to P ( 3c - 1 ) ...
... suspended equal weights P , P : to find the tensions of the several portions of the string , supposing AH , HK , KB , to be all equal . If AB = c , and 7 = the whole length of the string , the ten- sion of HK is equal to P ( 3c - 1 ) ...
Page 20
... suspended from a point O at a point of the string between the pegs : to find W in terms of P and Q in order that the angle AOB may be a right angle . The weight W is given by the relation W2 = P2 + Q2 . ( 4 ) Three forces act at the ...
... suspended from a point O at a point of the string between the pegs : to find W in terms of P and Q in order that the angle AOB may be a right angle . The weight W is given by the relation W2 = P2 + Q2 . ( 4 ) Three forces act at the ...
Page 34
... suspended at the end of a string the higher end O of which is fixed to a point in the former string : find the magnitude of the angle AOB , when there is equili- brium , and ascertain whether it is possible for O to lie in the line AB ...
... suspended at the end of a string the higher end O of which is fixed to a point in the former string : find the magnitude of the angle AOB , when there is equili- brium , and ascertain whether it is possible for O to lie in the line AB ...
Page 44
... suspended from its extre- mities , rests with its convexity downwards upon a horizontal plane ; to determine the position of equilibrium . Let AEB , fig . ( 43 ) , be the arc , resting at the point E on a horizontal plane . Let C be the ...
... suspended from its extre- mities , rests with its convexity downwards upon a horizontal plane ; to determine the position of equilibrium . Let AEB , fig . ( 43 ) , be the arc , resting at the point E on a horizontal plane . Let C be the ...
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Common terms and phrases
body is projected centre of gravity chord coefficient of friction collision component cos² cylinder denote described determine directrix distance equal forces equation feet find the position find the pressure fixed point forces act fulcrum geometrical progression given circle given point hangs hence highest point horizontal plane impact impinges inclined plane intersection join latus rectum lever line of quickest lowest point magnitude and direction mass middle point motion moveable parabola parallel parallelogram particle perfectly elastic ball perpendicular point of projection position of equilibrium pound weight pounds prove pully quickest descent radii radius ratio reaction respectively rest resultant right angles SECT shew sides sin² sliding smooth sphere straight line string passing supposing suspended tan¹ tangent three forces uniform rod velocity of projection vertex vertical circle vertical plane
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Page 255 - Classics, so far as they have been published, will be adopted. These editions have taken their place amongst scholars as valuable contributions to the Classical Literature of this country, and are admitted to be good examples of the judicious and practical nature of English scholarship ; and as the editors have formed their texts from a careful examination of the best editions extant, it is believed that no texts better for general use can be found. The volumes will be well printed at the Cambridge...
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