Elementary Mechanics |
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Page 9
... evidently keep in equilibrium a portion of the force P equal K A C B H to Q , and these two will neutralize each other , thus leaving a force PQ as the resultant force acting in the direction of H : take AB as before , equal to P units ...
... evidently keep in equilibrium a portion of the force P equal K A C B H to Q , and these two will neutralize each other , thus leaving a force PQ as the resultant force acting in the direction of H : take AB as before , equal to P units ...
Page 13
... evidently the same in magnitude and direction as that of the first pair ; and hence we come to the conclusion that it is indifferent as to statical effect , whether the resultant of the given forces P and Q + R acts at A 16. ] FORCES AT ...
... evidently the same in magnitude and direction as that of the first pair ; and hence we come to the conclusion that it is indifferent as to statical effect , whether the resultant of the given forces P and Q + R acts at A 16. ] FORCES AT ...
Page 14
... than AB ; which is evidently absurd . Hence AE is not the direction of the resultant of the given forces . In like manner it can be shewn that no other line except AD is in that direction , and therefore 14 [ Art . 16 STATICS .
... than AB ; which is evidently absurd . Hence AE is not the direction of the resultant of the given forces . In like manner it can be shewn that no other line except AD is in that direction , and therefore 14 [ Art . 16 STATICS .
Page 17
... evidently not necessary that the forces should lie in one plane . The converse of the polygon of forces cannot , as the triangle of forces , be affirmed ; for parallel - sided polygons have not neces- sarily their sides in the same ...
... evidently not necessary that the forces should lie in one plane . The converse of the polygon of forces cannot , as the triangle of forces , be affirmed ; for parallel - sided polygons have not neces- sarily their sides in the same ...
Page 36
... evidently similar to the triangles ABB ' , ACC ' , and ADD ' , respectively ; therefore AB ' = OF AB OA ' OF.AB or АВ ' = OA OG.AC Similarly AC = AD ' = OA OH.AD OA = AB ' EC C'D ' , = AB + AC ' AD . = Now , from equal triangles ...
... evidently similar to the triangles ABB ' , ACC ' , and ADD ' , respectively ; therefore AB ' = OF AB OA ' OF.AB or АВ ' = OA OG.AC Similarly AC = AD ' = OA OH.AD OA = AB ' EC C'D ' , = AB + AC ' AD . = Now , from equal triangles ...
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Common terms and phrases
accelerating force action of gravity angle annexed figure applied axis beam bisects body Cambridge centre of gravity centripetal force circle cloth coefficient of friction couple Crown 8vo curve cycloid cylinder diagonal distance Edition English Notes equal and opposite equation equi extremity F. D. MAURICE Fellow of St force of gravity forces acting friction ft² fulcrum Greek Text hence horizontal plane inclined plane indefinitely small interval John's College late Fellow Law of Motion length lever M.A. Fellow meet middle point moving P₁ parabola parallelogram of forces pass perpendicular point of application position of equilibrium produced proportional pulley radius reaction represent respectively rest resultant sewed shew sides smooth space sphere Statics straight line string supposed surface tension Theological Manuals three forces Trinity College uniform unit virtual velocities W₁ W₂ wheel
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