Elementary Mechanics |
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Page 5
... vertical line . A body when free and left to the action of gravity alone , will fall to the surface of the earth : a force sufficient to sustain it , i.e. to keep it at rest in opposi- tion to the force of gravity , will , by the ...
... vertical line . A body when free and left to the action of gravity alone , will fall to the surface of the earth : a force sufficient to sustain it , i.e. to keep it at rest in opposi- tion to the force of gravity , will , by the ...
Page 20
... vertical ; required the tensions of the strings . Let A be the ring , T , T the respective tensions of the strings , AT , AT " their directions . Then the point A is kept in equilibrium by the force W acting vertically downwards , and ...
... vertical ; required the tensions of the strings . Let A be the ring , T , T the respective tensions of the strings , AT , AT " their directions . Then the point A is kept in equilibrium by the force W acting vertically downwards , and ...
Page 24
... vertically down- wards and the two equal tensions T ; hence it is manifest that the direc- tion CW must bisect the angle ACB , or that the angles CAB , CBA are each equal : let ø be this C angle . In CA take any point E , draw ED ...
... vertically down- wards and the two equal tensions T ; hence it is manifest that the direc- tion CW must bisect the angle ACB , or that the angles CAB , CBA are each equal : let ø be this C angle . In CA take any point E , draw ED ...
Page 25
... vertical circle . Find their position of equilibrium . K Let A and B be the two particles whose weights are W and W ' respectively , and let a be the known angle subtended by the string AB at the centre C of the circle , the angle made ...
... vertical circle . Find their position of equilibrium . K Let A and B be the two particles whose weights are W and W ' respectively , and let a be the known angle subtended by the string AB at the centre C of the circle , the angle made ...
Page 26
... vertical through C in K ; then the sides of the triangle CAK are parallel , to and therefore proportional to , the forces which keep A in equilibrium ; therefore T AK = = sin 0 . .. ( 1 ) , W KC AC = cos 0 .... . ( 2 ) : KC R W ...
... vertical through C in K ; then the sides of the triangle CAK are parallel , to and therefore proportional to , the forces which keep A in equilibrium ; therefore T AK = = sin 0 . .. ( 1 ) , W KC AC = cos 0 .... . ( 2 ) : KC R W ...
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Common terms and phrases
accelerating force action of gravity angle annexed figure applied axis beam BERNARD DRAKE bisects body Cambridge centre of gravity centripetal force cloth coefficient of friction couple Crown 8vo curve cycloid cylinder diagonal distance Edition English Notes equal and opposite equation equi extremity F. D. MAURICE Fellow of St force of gravity forces acting ft² fulcrum Greek Text hence horizontal plane inclined plane indefinitely small interval John's College late Fellow Law of Motion length lever M.A. Fellow meet middle point moving P₁ P₂ parabola parallelogram of forces pass perpendicular point of application position of equilibrium produced proportional pulley radius reaction represent respectively rest resultant sewed shew sides smooth space sphere Statics straight line string supposed surface tension Theological Manuals three forces Trinity College uniform unit virtual velocities W₁ W₂ wheel
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