A Collection of Problems in Illustration of the Principles of Theoretical Hydrostatics and Hydrodynamics |
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Page 1
... centre of gravity of the surface of the solid below the surface of the fluid , then , A repre- senting the surface of the solid , we know that Σ ( Kx ) = Ax , and therefore the pressure on A is equal to gpДx , that is , to the weight of ...
... centre of gravity of the surface of the solid below the surface of the fluid , then , A repre- senting the surface of the solid , we know that Σ ( Kx ) = Ax , and therefore the pressure on A is equal to gpДx , that is , to the weight of ...
Page 2
... centre of gravity are known , this corollary enables us at once to determine the whole pressure upon it . COR . 2. Suppose that the area A is divisible into a finite number of areas of known magnitudes , A ,, A , A , & c . , the ...
... centre of gravity are known , this corollary enables us at once to determine the whole pressure upon it . COR . 2. Suppose that the area A is divisible into a finite number of areas of known magnitudes , A ,, A , A , & c . , the ...
Page 4
... centre of gravity , that is , of its middle point , below the surface of the fluid ; then , by COR . ( 1 ) , the ... centre of gravity of one being h , and of the other h ' , the pressures on the two ends are gp.r2h , gp.r2h ' . Again ...
... centre of gravity , that is , of its middle point , below the surface of the fluid ; then , by COR . ( 1 ) , the ... centre of gravity of one being h , and of the other h ' , the pressures on the two ends are gp.r2h , gp.r2h ' . Again ...
Page 5
... centre of gravity of the surface , which is evidently the middle point of the axis , being equal to 1⁄2 ( h + h ' ) , it follows that the whole pressure on the cylinder must be equal to πgpr ( r + 1 ) ( h + h ' ) . 3. An isosceles ...
... centre of gravity of the surface , which is evidently the middle point of the axis , being equal to 1⁄2 ( h + h ' ) , it follows that the whole pressure on the cylinder must be equal to πgpr ( r + 1 ) ( h + h ' ) . 3. An isosceles ...
Page 6
... centre of gravity of the surface of his body is 32 feet under water . " The surface of a middle - sized human body is about 10 square feet . Multiply then 32 , the depth of the center under water , by 10 , the surface of the body , and ...
... centre of gravity of the surface of his body is 32 feet under water . " The surface of a middle - sized human body is about 10 square feet . Multiply then 32 , the depth of the center under water , by 10 , the surface of the body , and ...
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Common terms and phrases
Albert Girard altitude angular velocity aperture axem axes axis vertical base Bernoulli body Bossut Bossut Traité Cambridge centre of gravity centre of pressure coinciding cone cos² cube Daniel Bernoulli denote the density denote the length depth determine distance dx dy Edition efflux elastic equal equation filled with fluid floating fluid displaced force free surface given hemisphere Hence humidum Hydrodynamique immersed vertically inclination incompressible fluid James Bernoulli lamina late Fellow latus rectum motion parabola parallel particles portion position of equilibrium position of rest problem quæ ratio required pressure resultant pressure right angles sesquialterum sin² small orifice solid cylinder specific gravity sphere supposed tangent Treatise triangle Trinity College unit of pressure University of Cambridge vertex vertical line vessel volume weight whole pressure
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