Page images


(62 - a®) $2 + (54-B4) m2 = 12-1; thus this equation represents a surface, and consequently the double definite integral, whose element is $ dn , expresses the volume contained within the given limits between this surface and the plane of (, n). This surface is represented in fig. 45, where oc=1, for since a’ and B2 are both less than 1, when Ś=1,f=n=0; and consequently the surface intersects the (-axis at c. For values of Ś a little less than 1, the equation gives impossible values to & and 7l; but gives possible values when Ġ is greater than 1; thus the surface lies above the point c. When &? + m2 = 1, $ = 0; consequently if a right circular cylinder, whose radius =0A=0B=1, and whose axis is oc, is described as in the fig., the surface (56) is asymptotic to it. Also as (56) is unchanged when Ġ is replaced by –Ś, another surface equal and similar to CRQ lies below the plane of ($,n), to which the cylinder is also asymptotic. Thus the integral (55) expresses the volume contained within the cylinder and between those two surfaces. Hereby also we have a further interpretation of the definite integral; for if we give to Š a value greater than 1, and take it to be constant, while & and n vary, that is, if we cut the surface by a plane parallel to that of ($, n), (56) shews that the curve of section is an ellipse ; such is rQ, of which the semi-axes are

182_11 762-1 i
182 - a2)

$? - 82); and of which therefore the area =


(52 -- a?)$(82—82) If S varies, the area of this ellipse will also vary by a narrow elliptical ring, of which the area = ad.

2 62–1

(82—a)(6282)+' consequently we may consider the element of the volume, which is expressed in the right-hand of (55), to be

$_1 78d.

(52 – a?)$(52-B2) 1 2 -1




ja; so that

[ocr errors]
[ocr errors]

M. Catalan *, the double integral in (37) is reduced to the single integral in (60).

241.] In review of the processes of the two preceding articles let it be observed, that in equations (39) and (45) we have da = {b2c2 (sin a)? (cos 3)2 +c2a? (sin a)? (sin B)2 + a2b2 (cosa)2} & sin a dadß,

a bécé sin n dn dy {a? (sin n)? (cos y)2 + 62 (sinn)" (sin y)2 + c (cos n)a}?' the former of which is irrational, and the latter is rational; so that by means of the following substitutions we have been able to transform an element-function involving irrational quantities into an equivalent in terms of rational quantities only; viz. by substituting

sin a cos B =

_ a sin n cos y


sin a sin 6 - 6 sin n sinys

[ocr errors]

cos in

P where p2 = a(sin n)2 (cosy)2 +62 (sinn)(sin y)2 +c(cosn)?; and

(sin a)? (cos 3)2 (sin a)2 (sin B)2 (cos a)3

a T62T ? Also equating the values of the elements given in (41) and (44), we have på sin a da = abc sin n dn dy.

(62) Hence by the substitutions of (61), the double integral

u sin a da JJ {62 cm (sin a)? (cosß)2 + ca? (sin a)” (sin B)2 + a2 62 (cosa)2}}' in which u is a rational function of sin a cos B, sin a sin B, and cos a, may be transformed into the following, which involves only rational quantities, viz. into

ao b2c u sin n dn dy Ja (sin n)" (cosy)2 +62 (sin n)" (sin y)2 +ca (cos n)?? the limits of the new variables being easily obtained from those of the former variables by means of equations (61).

Again, from (62) we have


[ocr errors]


2 * See Liouville's Journal, Vol. IV, page 323. The same method is ex. tended to integrals of higher orders and more variables; the discussion however of which is beyond the scope of the present work.

242.] As position in space may be determined by a system of polar coordinates, such as that explained in Art. 165, so may of course the equation to a surface be expressed in terms of these polar coordinates; in which case for the determination of the area it is necessary to express the area-element in terms of them, This may be found by transformation of either of the expressions given in (29) and (31). I propose however first to investigate the subject on principles purely geometrical, and subsequently by analytical transformation to exhibit the identity of the result with those thus determined.

Let P, fig. 42, be the point (r, 0,) on the surface whose equation is F (r,0,) = 0; let 8 and o vary; and let the radii vectores due to the partial variation of o, to the partial variation of , and to the total variation of 0 and $, respectively, intersect the surface in the points U, V, R, so that PURV is the surface-element. From p draw is at right angles to op, and cutting ou in s; then Ps = rdo,

Also from p draw pt at right angles to op, and cutting ov in t; then PT = pdø =rsin 0 do,

Also let op be produced to z; then from the geometry, as explained in Art. 165, it is plain that Ps, PT, PZ form a system of lines at P such that each one is at right angles to the other two; and consequently they may be considered as constituting a system of rectangular coordinates originating at P; we will employ them as such, and take PS, PT, Pz to be respectively the x-, Y-, 2-, axes. In reference to this system p is (0,0,0); u is (rde,0, (a) de); v is (0,r sin odo, (a) do). Hence, if da denotes the surface-element, which is approximately a parallelogram, of which P, U, V, R are the angular points,

da = {» (sin 6)2 + (sin o) = ( +105)*}'rdo dø. (63) :. =[{re (sin 6)2 + (sin o) () + (7)}'r do dø; (64) this integral being definite, and the limits being assigned by the circumstances of the problem.

243.] The preceding expression for the surface-element may also be derived by transformation of coordinates from the last of (29) by means of the formulæ given in (70), Art. 165. It will be

[ocr errors]

convenient to effect the transformation by first replacing x and y in terms of p and $, and subsequently replacing p and z in terms of r and 0.

Since x = p cos 0, y = p sin $, therefore dx dy = p dp do: and as after substitution the equation to the surface takes the form F (2,0, z) = 0, then, as in (190), Art. 107, Vol. I,

[ocr errors]

v = v) = 1.cos e – les signes

v = (net) Vals) sin ø + Cestou cos . By a similar process, since

w = (de) = (49) cos o – Ce) sipe, ?

[ocr errors]
[ocr errors]
[ocr errors]

Hence, substituting for (hr), squaring and adding,

[ocr errors][merged small][merged small]
[ocr errors]

. de 1 W

ersinod(rsin 8)do; (67) (9) cos 0 – 0 D) sine the integral of course being definite.

If the equation to the surface is given in the explicit form r = f(0, 0), so that r-f(0,0) = f(r, 0, ) = 0, then

[ocr errors]

which is the same expression as (64).

If the surface whose area is to be determined is a surface of revolution about the z-axis, then the equation to it is independent of d, and (69) becomes,

172) + Go { r sin 0 do do. (70)

If the whole surface is required, the -integration may be effected for the limits 27 and 0, and A = 25/{(r d0)2 + dr2}ł r sin 0.

(71) This result is manifestly identical with that given in equations (17) and (21) of the present chapter. Indeed this process is general, and includes all the preceding.

244.] The following examples are illustrative of the preceding general formulæ.

Ex. 1. To find the area of a spherical triangle.

Let abc be the triangle whose angles are A, B, C; and o the centre of the sphere. Let oc be the z-axis; and let the central plane containing the side as be inclined to the plane of (x, y) at an angle = a, and intersect it along the x-axis. Then the equation to this plane is tan 0 = cot a cosec $. Let do be the p-coordinate to A, and consequently po+c is the p-coordinate to B. Let r = a be the equation to the sphere, and let

@ = tan-1 cot a cosec 0. Then from (69),

[ocr errors]
[ocr errors][ocr errors]
[ocr errors]
[ocr errors][merged small][merged small][ocr errors][ocr errors][ocr errors][ocr errors][ocr errors][ocr errors]
« PreviousContinue »