## A Key to the Exercises and Examples Contained in a Text-book of Euclid's Elements |

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Page xi

The other two cases follow in a

AND , AMB . ( iv ) from the equal AS BNC , DMC . Page 17 B. 3. In the As OAM ,

OBM , OA = OB , being radii of a 0 , OM is common to the two As , and L AOM = _

...

The other two cases follow in a

**similar**manner by 1. 4 . ( iii ) from the equal ASAND , AMB . ( iv ) from the equal AS BNC , DMC . Page 17 B. 3. In the As OAM ,

OBM , OA = OB , being radii of a 0 , OM is common to the two As , and L AOM = _

...

Page 3

AOX and COY = a rt . L. 4. The cox is supplementary to Z AOX , and LAOX =

LBOX . The second case is

BOOK I. 3 PAGES 27 , 29 .

AOX and COY = a rt . L. 4. The cox is supplementary to Z AOX , and LAOX =

LBOX . The second case is

**similar**. Page 30 . By Ex . 6 , p . 1-2 EXERCISES ONBOOK I. 3 PAGES 27 , 29 .

Page 14

L. Also CA , AG = HA , AB ... A $ GAC , BAH are equal in all respects [ 1. 4 ] . The

other case is

respects [ 1. 4 ] . .. AX = BY . Similarly BY = cz . 4. Let BD be the diagonal of sq .

ABCD .

L. Also CA , AG = HA , AB ... A $ GAC , BAH are equal in all respects [ 1. 4 ] . The

other case is

**similar**. 3. It is easy to see that AS ACX , BCY are equal in allrespects [ 1. 4 ] . .. AX = BY . Similarly BY = cz . 4. Let BD be the diagonal of sq .

ABCD .

Page 26

( ii ) may be proved by a

AB , CD , the perp . EOF to these sides is equal to the perp . from A to CD . Thus

the As OAB , OCD , ADC have equal bases , and the altitude of ADC is equal to

the ...

( ii ) may be proved by a

**similar**method . 17. If o lies between the parallel sidesAB , CD , the perp . EOF to these sides is equal to the perp . from A to CD . Thus

the As OAB , OCD , ADC have equal bases , and the altitude of ADC is equal to

the ...

Page 55

26. Let - BGC = - EHF . Then the A ' BGC , EHF are identically equal . Also arc

BKC = arc ELF , and the whole o ce KBAC = whole .. remainder arc BAC = arc

EDF . .. LBKC = L ELF ( 111. 27 ] ... segments BKC , ELF are

on ...

26. Let - BGC = - EHF . Then the A ' BGC , EHF are identically equal . Also arc

BKC = arc ELF , and the whole o ce KBAC = whole .. remainder arc BAC = arc

EDF . .. LBKC = L ELF ( 111. 27 ] ... segments BKC , ELF are

**similar**: and they areon ...

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A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H S 1848-1934 Hall No preview available - 2018 |

A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H. S. Hall No preview available - 2017 |

### Common terms and phrases

ABCD angles Assistant base bisector bisects BOOK Cambridge centre chord circle College common constant containing describe diam diameter distance double draw drawn Edited ELEMENTARY ENGLISH equal EXAMPLES Exercises external Fcap Fellow figure fixed four given given st greater GREEK half Hence HISTORY identically equal Illustrated inscribed intersect Introduction JOHN Join LATIN Let ABC locus Master Mathematics meet middle point Notes parl parm passes perp plane preparation Press produced Prof Professor proved radius ratio rect respectively revised School segment shewn sides similar Similarly solutions Take tangent touch Translated triangle twice University vols

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