A Key to the Exercises and Examples Contained in a Text-book of Euclid's Elements |
From inside the book
Page 2
... Bisect the given st . line , and with the half line for the equal sides describe an isosc . A as in Ex . 1 , page 13 . Page ... bisects ABC , ACB of isosc . △ ABC , and let them meet in O. Then OBC , OCB being halves of equal angles are ...
... Bisect the given st . line , and with the half line for the equal sides describe an isosc . A as in Ex . 1 , page 13 . Page ... bisects ABC , ACB of isosc . △ ABC , and let them meet in O. Then OBC , OCB being halves of equal angles are ...
Page 3
... Bisect AB in C. Draw CX perp . to AB and equal to P. Join AX , BX . Then △ ACX , BCX are equal in all respects ; .. AX = BX . 14. A , B the given pts . , XY the given line . Join AB , and bisect it in C. Draw CP perp . to AB meeting XY ...
... Bisect AB in C. Draw CX perp . to AB and equal to P. Join AX , BX . Then △ ACX , BCX are equal in all respects ; .. AX = BX . 14. A , B the given pts . , XY the given line . Join AB , and bisect it in C. Draw CP perp . to AB meeting XY ...
Page 6
... Bisect POQ by OX meeting the other given st . line AB in X. From X draw XP , XQ perp . to the given lines . Then XP = XQ by I. 26 . If AB is par1 . to the bisector of the POQ , the pt . X cannot be found . 9. Let O be the given pt ...
... Bisect POQ by OX meeting the other given st . line AB in X. From X draw XP , XQ perp . to the given lines . Then XP = XQ by I. 26 . If AB is par1 . to the bisector of the POQ , the pt . X cannot be found . 9. Let O be the given pt ...
Page 7
... bisects BAC .. LZYA = L BYX = L Bad = dac = LYZA . 5. Let BA be produced to D , and let AX bisect DAC , and be par1 . to BC . Then ext . DAX int . opp . 4 ABC , and LXAC alt . = ACB . .. LABC LACB . = Page 59 . 1. ( i ) Let AD be par1 ...
... bisects BAC .. LZYA = L BYX = L Bad = dac = LYZA . 5. Let BA be produced to D , and let AX bisect DAC , and be par1 . to BC . Then ext . DAX int . opp . 4 ABC , and LXAC alt . = ACB . .. LABC LACB . = Page 59 . 1. ( i ) Let AD be par1 ...
Page 8
... bisect DBC by BE ; then ABC is trisected by BD , BE . For DBC = two - thirds of a rt . ≤ [ 1. 32 ] , . ' . △ DBE , EBC are each one - third of a rt . . 7 . Let the bisectors be BO , CO ; then BOC = suppt . of sum of OBC , OCB = suppt ...
... bisect DBC by BE ; then ABC is trisected by BD , BE . For DBC = two - thirds of a rt . ≤ [ 1. 32 ] , . ' . △ DBE , EBC are each one - third of a rt . . 7 . Let the bisectors be BO , CO ; then BOC = suppt . of sum of OBC , OCB = suppt ...
Other editions - View all
A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H S 1848-1934 Hall No preview available - 2018 |
A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H. S. Hall No preview available - 2017 |
Common terms and phrases
A. W. VERRALL AABC AB² ABCD AC² angles Assistant Master AX² BC² bisector bisects Cambridge centre chord circle circum College concyclic constant describe diam diameter diff draw ELEMENTARY equiangular equilat FASNACHT Fcap fixed point G. E. FASNACHT given base given point given ratio given st GREEK Hence identically equal inscribed intersect Introduction and Notes ISAAC TODHUNTER isosceles Join Let ABC LL.D locus M.A. BOOK meet middle point middle pt orthocentre Owens College par¹ parm pedal triangle perp plane produced Prof Professor Radical Axis radius equal rect respectively segment shewn sides Similarly sum of sqq tangent touch Translated triangle Trinity College vert vols
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