A Complete Key to Gummere's Surveying: In which the Operations of All the Examples, Not Solved in that Work are Exhibited at Large ... |
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Page 27
... secant of bearing 38 ° 30 ′ As rad . Is to tang . bearing 38 ° 30 ' So is diff . lat . 34.43 To departure 27.39 As radius Ar . Co. 8.46306 10.10651 Ar . Co. 0.00000 9.90061 1.53694 1.43755 EXAMPLE 4 . Ar . Co. 0.00000 10.07397 And , Is to ...
... secant of bearing 38 ° 30 ′ As rad . Is to tang . bearing 38 ° 30 ' So is diff . lat . 34.43 To departure 27.39 As radius Ar . Co. 8.46306 10.10651 Ar . Co. 0.00000 9.90061 1.53694 1.43755 EXAMPLE 4 . Ar . Co. 0.00000 10.07397 And , Is to ...
Page 29
... bearing S. 60 ° 8 ' W. And , As radius Is to secant bearing 60 ° 8 ' So is diff . lat . · To distance 12.27 1.02694 · 10.00000 · 10.24090 Ar . Co. 0.00000 · 10.30279 0.78604 1.08883 EXAMPLE 3 . Sta . Courses . Dist . N. S. 1 E. W. 1 S ...
... bearing S. 60 ° 8 ' W. And , As radius Is to secant bearing 60 ° 8 ' So is diff . lat . · To distance 12.27 1.02694 · 10.00000 · 10.24090 Ar . Co. 0.00000 · 10.30279 0.78604 1.08883 EXAMPLE 3 . Sta . Courses . Dist . N. S. 1 E. W. 1 S ...
Page 30
... bearing N. 10 ° 33 ' E. As radius Is to secant bearing 10 ° 33 ' So is diff . lat . 27.83 0.71433 0.00000 9.26982 Ar . Co. 0.00000 · 10.00740 1.44451 To distance 28.31 - · EXAMPLE 4 . 1.45191 Sta . Bearing . Dist . N. S. E. W. 1 S. 10 ...
... bearing N. 10 ° 33 ' E. As radius Is to secant bearing 10 ° 33 ' So is diff . lat . 27.83 0.71433 0.00000 9.26982 Ar . Co. 0.00000 · 10.00740 1.44451 To distance 28.31 - · EXAMPLE 4 . 1.45191 Sta . Bearing . Dist . N. S. E. W. 1 S. 10 ...
Page 32
... bearing N. 25 ° 15 ′ W. 9.63001 And , 54 Bearing 4th side N. 28 ° 45 ' E. As radius Is to cos . chang . bearing 25 ° 15 ' So is distance To diff . latitude 31.97 Ar . Co. 0.00000 9.95639 ... secant bearing 2 ° 32 [ CHAP . II . SURVEYING .
... bearing N. 25 ° 15 ′ W. 9.63001 And , 54 Bearing 4th side N. 28 ° 45 ' E. As radius Is to cos . chang . bearing 25 ° 15 ' So is distance To diff . latitude 31.97 Ar . Co. 0.00000 9.95639 ... secant bearing 2 ° 32 [ CHAP . II . SURVEYING .
Page 33
... secant bearing 2 ° 49 ′ So is diff . lat .. To distance EA 45.58 Ar . Co. 0.00000 · 10.00052 1.65830 1.65882 To find ... Bearing of EA · 2 ° 49 ' 16 EF S. 47 ° 1 ' W. To find EAF and bearing of FA : As AF 31.80 Is to EF 31.30 · So is sin ...
... secant bearing 2 ° 49 ′ So is diff . lat .. To distance EA 45.58 Ar . Co. 0.00000 · 10.00052 1.65830 1.65882 To find ... Bearing of EA · 2 ° 49 ' 16 EF S. 47 ° 1 ' W. To find EAF and bearing of FA : As AF 31.80 Is to EF 31.30 · So is sin ...
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Common terms and phrases
AB² AB³ ABCD angles and side B{sin BC+AC bearing 25 bearing 32 bearing 66 bearing and distance BENJAMIN HALLOWELL bisect Calculation centre changed bearing COMLY'S Construction cosec Demonstration departure describe the semicircle diff Dist division line draw equal Euclid EXAMPLE find AC find CD find log find the angle given area given bearings given distances given side GUMMERE'S SURVEYING Half sum Hence join N.
S.
E.
W.
E. D. D. W. D. D. Mult N.
S.
E.
W. Cor North parallel PROBLEM 12 pronunciation protract the figure QUESTION radius To tang rectangle secant bearing secant of bearing similar triangles spelling SPELLING-BOOK square triangle ABC words
Popular passages
Page 54 - AB, equal to the greater of the given sides '(20). Draw BD perpendicular to AB, equal to twice the given area, divided by AB (12.39). Through D draw DC parallel to AB. Then if AC be made equal to the other given side (16.25), and BC be joined ; ABC will be the triangle. For the Division Line. Make AP = 8.50 the given distance. Take AF to AC in the ratio of the part to be cut off to the whole area. Join PF, draw BG parallel to it ; then PG will be the division line. Demonstration. AB : AP : : AG :...
Page 76 - AB, (PL 4, fig. 9.) = the given side, and divide it in D, so that AD may be to DB in the ratio of 3 to 2 ; in AB produced, take DO a fourth proportional to...