## A Key to the Exercises and Examples Contained in a Text-book of Euclid's Elements |

### From inside the book

Results 6-10 of 77

Page 19

Let ABCD be the

and De be perps . on this line . Through c draw CH par to EF meeting FB in H.

Then it is easily seen that AS BCH , DAE are identically equal [ 1. 26 ] ; .. BH = DE

. : .

Let ABCD be the

**given**parm . Through a draw any**st**. line EAF and let CX , BFand De be perps . on this line . Through c draw CH par to EF meeting FB in H.

Then it is easily seen that AS BCH , DAE are identically equal [ 1. 26 ] ; .. BH = DE

. : .

Page 21

Let AB be the

ABD each equal to the angle of an equilat . A. Through P and a draw st . lines par

! to AC , BD meeting AB in X and Y and intersecting in Z. Then XYZ is the ...

Let AB be the

**given st**. line , P and Q the given points . At A and B make 48 BAC ,ABD each equal to the angle of an equilat . A. Through P and a draw st . lines par

! to AC , BD meeting AB in X and Y and intersecting in Z. Then XYZ is the ...

Page 22

Let o be the given pt . , AB and CD the two

nearer to O. Draw OEF perp . to AB , CD respectively , and og perp . to OF making

OG equal to OF . Draw GH perp . to AB ; join Oh , and draw OK perp . to OH

meeting ...

Let o be the given pt . , AB and CD the two

**given st**. lines of which AB is thenearer to O. Draw OEF perp . to AB , CD respectively , and og perp . to OF making

OG equal to OF . Draw GH perp . to AB ; join Oh , and draw OK perp . to OH

meeting ...

Page 23

90 , it is shewn that AX = XC , and BX = BC . Thus CBX is the required triangle . 5.

This is clearly a particular case of the preceding example . 6. Let P , Q be the

is ...

90 , it is shewn that AX = XC , and BX = BC . Thus CBX is the required triangle . 5.

This is clearly a particular case of the preceding example . 6. Let P , Q be the

**given**pts . through which the sides are to pass , XY the**st**. line in which the baseis ...

Page 26

Let ABC be the

the required 4 , and by Ex . 21 draw through D a

E , so that ADBE may be equal to A ABC . 23. Let CAB be the

.

Let ABC be the

**given**A , and B the**given**L. In BA take BD equal to the base ofthe required 4 , and by Ex . 21 draw through D a

**st**. line to meet BC produced inE , so that ADBE may be equal to A ABC . 23. Let CAB be the

**given**A on base AB.

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A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H S 1848-1934 Hall No preview available - 2018 |

A Key to the Exercises and Examples Contained in a Text-Book of Euclid's ... H. S. Hall No preview available - 2017 |

### Common terms and phrases

ABCD angles Assistant base bisector bisects BOOK Cambridge centre chord circle College common constant containing describe diam diameter distance double draw drawn Edited ELEMENTARY ENGLISH equal EXAMPLES Exercises external Fcap Fellow figure fixed four given given st greater GREEK half Hence HISTORY identically equal Illustrated inscribed intersect Introduction JOHN Join LATIN Let ABC locus Master Mathematics meet middle point Notes parl parm passes perp plane preparation Press produced Prof Professor proved radius ratio rect respectively revised School segment shewn sides similar Similarly solutions Take tangent touch Translated triangle twice University vols

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