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Books Books 41 - 50 of 162 on The opposite angles of any quadrilateral figure inscribed in a circle, are together....
" The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles. "
Pure Mathematics - Page 273
1874
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Minutes of the Committee of Council on Education, with Appendices, Volume 2

Great Britain. Privy Council. Committee on Education - 1850
...the whole and one of the parts may be equal to the squire of the other part. 4. Prove Euc. III. 22. The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. 4. Solve Euc. IV. 6. To inscribe a square in a given circle. 6. Prove Euc. V. 5. If one magnitude be...
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Reports on Elementary schools

Her MAjesty' Inspectors of schools - 1850
...upon equal bases, and between the same parallels, ore equal to one another. 4. Prove Euc. III. 22. The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. 6. Prove Euc. V. 5. If one magnitude be the same multiple of another which a part taken from the first...
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The English journal of education, ed. by G. Moody

George Moody - 1851
...with the square of the line between the points of section, is equal to the square of half the line. 3. The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. 2. To describe a square that shall be equal to a given rectilineal figure. SECTION III.—1. In a circle...
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A collection of problems and examples, adapted to the "Elementary course of ...

Harvey Goodwin - Mathematics - 1851 - 173 pages
...shew that four times the sum of the squares of BE and CF is equal to five times the square of BC. 3. The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. If a polygon of an even number of sides be inscribed in a circle, the sum of the alternate angles together...
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THE PRINCIPLES OF THE SOLUTION OF SENATE-HOUSE 'RIDERS'

FRANCIS J. JAMESON - 1851
...subtended by BD at the centre = 2ZBCD. Therefore zAOC + zBOD =* 2zEBC + 2/ECB, = 2ZAEC. 1851. (A). The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles, (in. 22.) (jB). If a polygon of an even number of sides be inscribed in a circle, the sum of the alternate...
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Five Years in an English University, Volume 2

Charles Astor Bristed - 1852
...incidence. MISCELLANEOUS QUESTIONS. TRINITY COLLEGE. June, 1843. four Hours. 1. THE opposite angles of a quadrilateral figure inscribed in a circle are together equal to two right angles. 2. If there be any number of equal ratios a : b = a, : 6[ = a* : b^, ifec., each of them is equal to...
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The synoptical Euclid; being the first four books of Euclid's Elements of ...

Euclides - 1853
...BAD is equal to the whole angle BED. Wherefore the angles in the same segment, &c. UKD PROP. XXII. THEOREM. The opposite angles of any quadrilateral...two right angles. Let ABCD be a quadrilateral figure in the circle ABCD; any two of its opposite angles are together equal to two right angles. 1) Join...
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The geometry, by T. S. Davies. Conic sections, by Stephen Fenwick

Royal Military Academy, Woolwich, Thomas Stephens Davies, Stephen Fenwick, William Rutherford - Mathematics - 1853
...segment, etc. QED PROPOSITION XXII. THEOR. The opposite angles of any quadrilateral figure inscriled in a circle, are together equal to two right angles. Let ABCD be a quadrilateral figure in the circle ABCD : any two of its opposite angles are together equal to two right angles. Join AC,...
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The Elements of Euclid, books i-vi; xi. 1-21; xii. 1,2; ed. by H.J. Hose

Euclides - 1853
...proved. PEOP. XXII. THEOE. The opposite angles of any quadrilateral figure inscribed in a circle shall he together equal to two right angles. Let ABCD be a quadrilateral figure inscribed in the circle ABC. Then each pair of its opposite angles shall be equal to two right angles. I. The opposite angles...
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Solutions of the problems and riders proposed in the Senate-house ...

Cambridge univ, exam. papers - 1854
...Euclid's figure, the rectangle contained by CF and FA is proved to be equal to the square on CA. 3. The opposite angles of any quadrilateral figure inscribed...in a circle are together equal to two right angles. If the opposite sides of the quadrilateral be produced to meet in P, $, and about the triangles so...
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